hw2-solution

# hw2-solution - COMP362 Assignment 2 1 a) The probability...

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COMP362 Assignment 2 1 a) The probability that a packet can reach B is that the packet is successfully received at every step. Thus the probability is 0 . 8 9 = 0 . 11. It can be seen that even the probability of every link is relative high, the end to end receive probability is still low. b)Assume the probability of every link is p . We have p 9 = 0 . 8 which shows that p = 0 . 97. 2 By applying Z i,m = d i * c m and Z * i,m = N s =1 Z S i,m , the data sent by sender1 is ( - 1 , - 1 , 1 , 1 , 1 , 1 , - 1 , - 1 , 1 , 1 , - 1 , - 1 , - 1 , - 1 , 1 , 1) and the data sent by sender2 is(1 , 1 , 1 , - 1 , 1 , 1 , - 1 , 1 , 1 , 1 , 1 , - 1 , 1 , 1 , - 1 , 1). The aggregate result received by receiver is (0 , 0 , 2 , 0 , 2 , 2 , - 2 , 0 , 2 , 2 , 0 , - 2 , 0 , 0 , 0 , 2). By applying d i = 1 M M m =1 Z * i,m * c , we can compute at the receiver that the bits sent by sender1 is (1 , - 1) and sender2 is (1 , 1). 3 Suppose station A and C are transmitting to station B. A and C can not hear each other’s transmissions. However A’s and C’s transmissions are

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## hw2-solution - COMP362 Assignment 2 1 a) The probability...

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