HW1 Solution - CEIE 340 Homework 1 Solutions Fall 2006...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
CEIE 340 Homework 1 Solutions Fall 2006 YHK Page 1 of 6 Problem 2: problem 1.9 on page 26 The pump equation is: e QH P γ = 0 Where, P 0 = power output γ = specific weight of the fluid Q = flow rate H = the total head e = efficiency The efficiency could be estimated by measuring the flow rate and the power output for a given head. In the synthesis case, the efficiency will be indicated on the pump, while Q and H can be measured. Problem 3: problem 1.11 on page 26 Vp = precipitation volume ft acre mi acre in ft mi in V p = = 600 , 95 1 997 . 639 . 12 . 1 ) 200 .( 9 2 2 ft acre ft acre V V p s = = = 200 , 19 ) 600 , 95 ( 2 . 0 2 . 0
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
CEIE 340 Homework 1 Solutions Fall 2006 YHK Page 2 of 6 Problem 4: problem 1.12 on page 26 tP i R i P R P - R A c u m 000 - - - - 10 0.07 2.1 16,516.50 1,260.00 15,256.50 15,256.50 20 0.15 9.5 35,392.50 5,700.00 29,692.50 44,949.00 30 0.21 18.9 49,549.50 11,340.00 38,209.50 83,158.50 40 0.16 37.3 37,752.00 22,380.00 15,372.00 98,530.50 50 0.09 48.8 21,235.50 29,280.00 -8,044.50 90,486.00 60 0.05 52.6 11,797.50 31,560.00 -19,762.50 70,723.50 i i P P acre ft in ft acre P 950 , 235 1 43560 12 1 65 2 = = i i R R R 600 min sec 60 min 10 = = Problem 4 0.E+00 2.E+04 4.E+04 6.E+04 8.E+04 1.E+05 1.E+05
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/11/2009 for the course CEIE 340 taught by Professor Choudhury during the Spring '09 term at George Mason.

Page1 / 6

HW1 Solution - CEIE 340 Homework 1 Solutions Fall 2006...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online