Homework_6_2007

Homework_6_2007 - ECE 154B Homework#6 Due March 7 2007 1...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECE 154B Homework #6 Due March 7, 2007 1. Making the usual assumptions of equally likely signals in AWGN and an optimal receiver, it can be shown that the probability of symbol error for M/2 orthogonal signals of energy E and their negatives is given as: P[symbol error] = 1 - π 2 1 dx x Q E x M N 2 2 2 )) ( 2 1 ]( ) 2 ( 2 1 exp[- ∞--- ∫ A special case of this for M=4 is the case of QPSK where the 4 signals are: + sin( ϖ t), -sin( ϖ t), + cos( ϖ t), and - sin( ϖ t). For this case, we have derived a formula in class for the probability of symbol error. Show how the above formula reduces to the formula we derived in class. 2. For the case of 4 orthogonal signals and their negatives (i.e., M=8) how should we map 3 binary digits to the 8 waveforms to minimize the probability of binary error at high signal to noise ratio? 3. Do a simulation that simulates the situation described in problem 2. Show how a poor mapping of 3 binary digits to the 8 waveforms results in a larger probability of binary error...
View Full Document

{[ snackBarMessage ]}

Page1 / 2

Homework_6_2007 - ECE 154B Homework#6 Due March 7 2007 1...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online