This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: Answer in units of J. Hot Reservoir Temperature 22:04, trigonometry, numeric, > 1 min, nor-mal. 006 A Carnot engine has an e f ciency of 25 percent when the hot reservoir tempera-ture is 500 C. If we want to improve the e f ciency to 30 percent, what should be the temperature of the hot reservoir, assuming everything else remains unchanged? Answer in units of C. Refrigerator Performance 02 22:06, trigonometry, numeric, > 1 min, nor-mal. 007 A refrigerator has a coe f cient of performance equal to 5. If the refrigerator absorbs 120 J of thermal energy from a cold reservoir in each cycle, nd the work done in each cycle. Answer in units of J. 008 Find the thermal energy expelled to the hot reservoir. Answer in units of J. Answers: 001: 0.485022 C 002: 0.0694444 003: 335 J 004: 8.69625 x 10 8 J 005: 3.29625 x 10 8 J 006: 555.214 C 007: 24 J 008: 144 J 021: 9.94718 x 10-5 C/m 2 022: :-X...
View Full Document
This note was uploaded on 11/12/2009 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.
- Spring '08