lecture 4 - * &...

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Unformatted text preview: * & &&& & 11/12/09 9/10 lecture 4 Sunghoon Kwon Slide credit: Professor Roger Howe, Stanford 11/12/09 A Second Order System v S ( t ) L v C ( t ) +- R C i L i R i C v L + - Where does the inductor come from? (~ 1nH/mm for any wire) Do step response: vS ( t ) jumps to VDD at t = 0 t = 0 VD D 11/12/09 Step Response of R-L-C circuit v S ( t ) L v C ( t ) +- R C i L i R i C v L + - Initial conditions: vC ( t =0-) = 0 V & iL ( t =0-) = 0 A C L i i = ( 29 dt dv C t d t v L C t L = 1 + - = C C DD L v R dt dv C V v Inductor voltage: t = 0 VD D C L R i i i = = for t 0 11/12/09 Second-Order Differential Equation for vC(t) dt dv C t d v R dt dv C V L C t C C DD = + - 1 Substituting for vL : 2 2 1 dt v d C v R dt dv C V L C C C DD =...
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This note was uploaded on 11/12/2009 for the course EE 420.402 taught by Professor Lee during the Spring '08 term at Seoul National.

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lecture 4 - * &...

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