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lecture 4

lecture 4 - ı&&&&& 9/10 lecture 4 Sunghoon...

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Unformatted text preview: ı * & &&& & 11/12/09 9/10 lecture 4 Sunghoon Kwon Slide credit: Professor Roger Howe, Stanford 11/12/09 A Second Order System v S ( t ) L v C ( t ) +- R C i L i R i C v L + - Where does the inductor come from? (~ 1nH/mm “for any wire”) Do step response: vS ( t ) jumps to VDD at t = 0 t = 0 VD D 11/12/09 “Step Response” of R-L-C circuit v S ( t ) L v C ( t ) +- R C i L i R i C v L + - Initial conditions: vC ( t =0-) = 0 V & iL ( t =0-) = 0 A C L i i = ( 29 dt dv C t d t v L C t L = ′ ′ ∫ 1 + - = C C DD L v R dt dv C V v Inductor voltage: t = 0 VD D C L R i i i = = for t 0 ≥ 11/12/09 Second-Order Differential Equation for vC(t) dt dv C t d v R dt dv C V L C t C C DD = ′ + - ∫ 1 Substituting for vL : 2 2 1 dt v d C v R dt dv C V L C C C DD =...
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lecture 4 - ı&&&&& 9/10 lecture 4 Sunghoon...

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