test3math1501 - between [2 , 6]. Hence, nd max x [2 , 6] f...

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Georgia Tech FALL 2009 Heinrich Matzinger QUIZ 3 FOR MATH 1501: CALCULUS I 1) Let f ( x ) = x 3 3 - 3 . 5 x 2 + 6 x + 1 . Find the all the places where f ( x ) = 0. 2) Same f ( x ) as in previous problem. Where is f increasing, where is it decreasing? 3) Same f ( x ) as in problem 1. Where is f ( x ) concave down and where is it concave up? 4) Same f ( x ) as in problem 1. If we restrict f to the interval between 0 and 2. Where does f reach its maximum value on that interval and what is it? Hence determine max x [0 , 2] f ( x ) as well as x 0 [0 , 2] such that f ( x 0 ) f ( s ) for all s [0 , 2]. 5) Same f ( x ) as in problem 1. Where does f reach its maximum if we restrict it to the interval
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Unformatted text preview: between [2 , 6]. Hence, nd max x [2 , 6] f ( x ) as well as x [2 , 6] so that f ( x ) f ( s ) for all s [2 , 6]. 6) Determine the limit lim n n 3 + 1000 n 2 + 343 n + 10 . 001 n 4 + 1 7) Determine the limit lim n (1 + (0 . 5 /n )) . 1 n 8) Determine the limit lim n 3 n + 2 n 100 (3 n ) 9) Determine the limit lim n 3 2( n 2 +1) /n 2 . 10) What is the approximate value of (1 . 0001) 20000 ?...
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test3math1501 - between [2 , 6]. Hence, nd max x [2 , 6] f...

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