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ECE201_Review_Exam_1

# ECE201_Review_Exam_1 - EE-201 Review Probs Test 1 page-1...

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Unformatted text preview: EE-201, Review Probs Test 1 page-1 Spring 98 E E - 2 01 Review Exam I Multiple Choice (5 points each, no partial credit.) 1. The voltage Vx in the circuit below is: (a) 3V (b) 2V (c) -2V (d) 1V (e) -1V 2. Consider the circuit below where each shaded box is a general circuit element. What is the current I? (a) 8A (b) 7A (0) -7A (d) 3A (e) -3A 3. If Im = 7A, the current Iout = (in amps): (a) 3 (b) 1 (o) 14/11 (d) 4 (e) None of above IQ 1m 0 “out 29 EE-201, Review Probs Test 1 page-2 Spring 98 4. This is a conceptual problem and requires no calculations for the answer. Consider the circuits below. All resistors are 19 except the one labeled R52. The difference between Ram and Rqu is the presence of the RS2 resistor between points a and b. eql Circuit 1 Circuit 2 The equivalent resistances seen between the inputs of cirCuits 1 and 2, Req1 and Rqu’ respectively, satisfy (a) Req1 > Req2 for any R (b) Req1 < Rqu for any R (0) Ram = Req2 for any R (d) There is no general relationship between Req1 and Rqu. it depends on the value of R. (e) None of above 5. in this problem, we model an operational amplifier as voltage controlled voltage source having a finite voltage gain A: Suppose an operational amplifier is connected in the so called voltage follower configuration below. EE-201, Review Probs Test 1 Spring 98 The voltage across the terminals of the op-amp, V+ - V_ , is: (a) V+-V_=O (b) V+—V_=AVi (c)V+-V_=Vi/A (d) V+ - V- = Vi/ (1+A) (e) None of above 6. For the circuit below, an appropriate nodal equation at the indicated supernode is: (a) 3Va+.5Vb=11 (b) 3Va+.5Vb=15 (c) 1.5Va+.5Vb=-11 (d) 1.5Va + 2Vb =11 (e) none of above in 7. Referring again to the circuit of problem 6, the node voltage Vb = (in volts): (a) 0 (b) 2 (c) 4 (d) 10 (e) none of these 8. in the circuit below, if v1(t) = 12V and i1(t) = 6A, then Vout“) = (in volts): (a) 40 (b) 22 (c) 16 (d) 6 (e) 4 O + o o Spring 98 EE-201, Review Probs Test 1 page-4 9. The mesh equations for the circuit below are: 2 - 4 -0.5 it V1 -1.5 6.5 -2.5 i2 = ‘V2 -o.5 -2.5 3.5 is 0 Then R2 = (in \$2): (a) 0.5 (b) 2.5 (c) -4.5 (d) 1.5 (9) none of these R4 V10 10. 0% O For the circuit below, the contribution to the output voltage by v1 = 26V with i1 = O is 8V. With v1 = O and i1 = 13A, the contribution to the output voltage is 9 volts. If v1 = 13 volts and i1 = 26A, then Vout = (in volts): (a) 20.5 (b) 22 (c) 17 (d) 34 (9) none of these 11. Find the current iy (in Amps), for the circuit shown below. (a) 5 (b) 1 (c) -2 (d) 10 (e) none of these EE-201, Review Probs Test 1 page-5 Spring 98 12. The linear network in the box in the circuit below contains at most resistors and linear dependent sources. Two separate dc measurements are taken from the circuit. in the first experiment it is found that when VS = 7 Volts and IS = 3 Amps the load current is Iload = 1 Amp. in the second experiment it is found that VS = 9 Volts and IS = 1 Amp yields a load current of Iload = 3 Amps. Find the load current, Iload: (in Amps) when Vs = 5 Volts and IS = 10 Amps Hint Either superposition or linearity must be used to solve this problem. You should obtain two equations in two unknowns (c) 9/11 (d) -1/2 (e) none ofthese 13. The linear network in the box contains at most resistors and linear dependent sources. For an input voltage of VS = 10 Volts the power supplied by the voltage source is found to be 20 Watts. If the source voltage is changed to V5 = 2 Volts, find the power supplied by the voltage source (in Watts). (a) 2/3 (b) 10 (c) 4/5 (d) 4 (e) none of these Linear vs 0 Network 14. For the network shown below, find the Thevenin equivalent resistance (in Ohms) seen looking into terminals a-b. (a) 15 (b) 5 (c) 20 (d) 10 (e) none of these EE-201, Review Probs Test 1 page—6 Spring 98 15. For the circuit of Problem 14, find the Thevenin equivalent voltage seen looking into terminals a-b. Recall that this is the open circuit voltage, Vab’ labeled in the circuit of Problem 14. The choices below are given in Volts. Hint Consider mesh analysis or voltage division. (a) -2 (b) 30 (c) -15 (d) 5 (e) none of these 16. The linear circuit below is found experimentally to have the voltage and current relationship shown. Which of the following circuits is its Norton equivalent? 1 Amps O a 2A0 0.59 4A0 0.59 o b EE-201, Review Probs Test 1 page-7 Spring 98 ’ a 0 a 4A 0 29 6A01009 . b . b (e) . a 4A 0 0.59 ob 17. The current i(t) is as shown in the graph below. The charge that is transported by the current i(t) through the surface SO of the conductor also illustrated below during the time interval, 0 s t s 3 seconds is (in Coulombs): (a) 7.5 (b) -7.5 (c) 15(d) 10 (e) none of above 18. The maximum power that can be delivered to the load, RL, is (in watts): Hint: Consider source transformations. (a) 25 (b) 5 (c) 1.25 (d) 2.5 (e) none of above 19. For the below circuit, the voltage drop V1: (in volts): EE-201, Review Probs Test 1 page-8 Spring 98 (a) 6.4V (b) -6.4V (0) 3.2V (d) —2.6V (e) none ofthese 20. Again consider the circuit of problem 19. The voltage drop, V2, across the independent current source in volts is: (a) 24.8V (b) 23.2V (0) 17V (d) 41.8V (e) none of these 21. Below is the graph of a circuit. All voltages are in volts and all currents are in amps. The value of the voltage, VBE, is (in V): (1) -29 (2) -21 (3) -13 (4) -4 (5) 17 (6) 29 (7) none of above 22. Referring again to the circuit graph of problem 1, the current ix = (in A): (1) -4 (2) -3 (3) 0 (4) 4 (5) 6 (6) cannot be determined (7) none of above 23. The power absorbed by the resistor in the circuit below is 15 watts. The value of the resistor is R = (in Q): (1) 2/3 (2) 1.5 (3) 2.582 (4) 6.667 (5) 1O (6) 15 (7) none of above EE—201, Review Probs Test 1 page-9 Spring 98 10V 0 R 24. The value of R which makes Fleq = 652 is (in S2): (1) 36 (2) 12 (3) 9 (4) 69 (5) 15 (6) 4 (7) none of above O 39 Re q -—-+ R 1252 25. Consider the circuit below. The voltage, vx = (in V): (1) 26 (2) 20 (3) 14 (4) 11.38 (5) 10 (6) 8 (7) none of above 69 + 69 26V 0 Vx ZOQ 26. In the circuit below, V1 = 70V and V2 = 20V. The value of R1 necessary to achieve these voltages is (in S2): (1) 140 (2) 100 (3) 50 (4) 42 (5) 40 (6) 20 (7) none of aobve EE—201, Review Probs Test 1 page-1O Spring 98 + V1 27. The value of Ix in the circuit below is (in A): (1) 48 (2) 27 (3) 18 (4) 12 (5) 9 (6) 6 (7) 3 28. In the circuit below, the value of R (in Q.) for which 11 = 2A is: (1) 85 (2) 50 (3) 35 (4) 2.08 (5) 100 (6) 213.6 (7) none of above 29. The equivalent resistance, Req, seen by the current source, IS, equals (in S2): (1) -0.6 (2) 9 (3) ~9 (4) -3 (5) 3 (6) 1 (7) -1 EE-201, Review Probs Test 1 page-11 Spring 98 30. The value of R for which the power delivered to the 109 resistor is 10 watts is (in S2): (1) 2kg (2) ZOkQ (3) 50052 (4) 509 (5) 200k§2 (6) 4kg (7) none of above 31. If the input voltage V31 = 10V and the input voltage V52 = 5V, then Vout = (in V): (1) 20 (2) 15 (3) -1O (4) 5 (5) 0 (6) -15 (7) none of above 32. The input voltage, Vs = 10V. The output voltage, Vout = (in V): (1) 2/3 (2) 14 (3) 15 (4) —150 (5) 140 (6) -140 (7) 150 EE—201, Review Probs Test 1 page-12 Spring 98 Work Out Problem: (28 pts) Consider the circuit below: (i) (2 pts) Identify the apprpriate supernode. (ii) (16 pts) Write a set of nodal equations for the circuit (iii) (4 pts) Reduce the nodal equations to a set of two equations in the variables VA and V0 only. (iv) (6 pts) Solve the nodal equations of part (iii) by any means you choose. You may use the trick formula labil- 1i" 'bi cd — ad-bc -c a if you want to. Specify VA, VB, and VC. ...
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