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ioe366f09-MidtermExam-Solution

# ioe366f09-MidtermExam-Solution - IOE 366 Fall 2009 Midterm...

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IOE 366 Fall 2009 Midterm Exam - Solution Part 1. Multiple Choice and Fill-in the Blanks(20 points total, 4 points each) 1. In single-factor ANOVA, SST – SSTr = _ SSE ___. 2. In a single-factor ANOVA problem involving five levels or treatments, which of the following statements are true about the alternative hypothesis? A. All five population means are equal. B. All five population means are different. C. At least two of the population means are different. D. At least three of the population mean are different. 3. 3. In single-factor ANOVA, the _ MSE __ is a measure of within-treatment variation, whereas_ MSTr _ is a measure of between-treatments variation. The ___ F __test statistic is formed by the ratio of ___ MSTR ___/____ MSE ____ 4. In a two-factor experiment where factor A consists of 4 levels, factor B consists of 3 levels, there is no interaction term, and there is only one observation on each of the treatment combinations, SST has ____ 11 ____ degrees of freedom, SSA has____ 3 ____degrees of freedom, SSB has __ 2 ____degrees of freedom and SSE has____ 6 _____degrees of freedom. 5 . Aexperiment has ____ 3 ____ factors, and each factor has ___ 2 _____ levels. If we were to run 3 replicates, the total number of experimental runs would be 24 . 1 of 8

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IOE 366 Fall 2009 Midterm Exam - Solution Part 2. Computational Problems (80 points total) Problem 1. (30 points) A field test for detecting the presence of arsenic has been proposed for use among forestry workers. The experiment compared the test as performed by both a trainee and an experience trainer to an analysis at a remote lab. Four subjects were selected for testing and are considered blocks. The response variable is arsenic content (in ppm).
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ioe366f09-MidtermExam-Solution - IOE 366 Fall 2009 Midterm...

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