IOE 366 Fall 2009
Midterm Exam  Solution
Part 1. Multiple Choice and Fillin the Blanks(20 points total, 4 points each)
1. In singlefactor ANOVA, SST – SSTr = _
SSE
___.
2. In a singlefactor ANOVA problem involving five levels or treatments, which of the following
statements are true about the alternative hypothesis?
A.
All five population means are equal.
B.
All five population means are different.
C.
At least two of the population means are different.
D.
At least three of the population mean are different.
3. 3. In singlefactor ANOVA, the _
MSE
__ is a measure of withintreatment variation,
whereas_
MSTr
_ is a measure of betweentreatments variation. The ___
F
__test statistic
is formed by the ratio of ___
MSTR
___/____
MSE
____
4. In a twofactor experiment where factor
A
consists of 4
levels, factor
B
consists of 3 levels,
there is no interaction term, and there is only one observation on each of the treatment
combinations,
SST
has ____
11
____ degrees of freedom, SSA has____
3
____degrees of
freedom, SSB has __
2
____degrees of freedom and SSE has____
6
_____degrees of freedom.
5
.
Aexperiment has ____
3
____ factors, and each factor has ___
2
_____ levels. If we were to run
3 replicates, the total number of experimental runs would be
24
.
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IOE 366 Fall 2009
Midterm Exam  Solution
Part 2. Computational Problems (80 points total)
Problem 1. (30 points)
A field test for detecting the presence of arsenic has been proposed for
use among forestry workers. The experiment compared the test as performed by both a trainee
and an experience trainer to an analysis at a remote lab.
Four subjects were selected for testing
and are considered blocks.
The response variable is arsenic content (in ppm).
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 Fall '08
 GAME
 Degrees Of Freedom, Errors and residuals in statistics, Alternative complement pathway

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