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# Ch8 - PD_110 l = sqrt[4R^2(4R*rt(3)^2 = 4R*rt(2/rt(3 so A =...

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Sheet1 Page 1 CH 8 - DEFORMATION Slip system: compare planar density for (100) (110) (111) FCC planes PD_110 = 1/(4R^2*sqrt(2) PD_100 = 2 atoms/8R^2 = 1/4R^2 PD_ 111: (4R)^2 = h^2 + (2R)^2 so h = 2*rt(3)*R and A = 1/2b*h so PD_111 = 2atoms/4*rt(3)*R^2 = 1/2R^3*rt(3) Planar densities for (100) (110) (111) BCC planes PD_100: A=(4R/rt(3))^2 = 16R^2/e so PD_100 = 1atom/(16R^2/3) = 3/16R^2
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Unformatted text preview: PD_110: l = sqrt[4R^2 + (4R*rt(3))^2] = 4R*rt(2)/rt(3) so A = l*w = 16R^2*rt(2)/3 and PD_100 = 2 atoms/(16*R^2*rt(2))/3 = 3/(8 R PD_111: base diagonal = a*rt(2) = 4*rt(2)*R/rt(3) h (height of triangle in cube) = sqrt((.5d)^2+d^2) = rt(40/3)*R so A = 1/2*d*h and PD = 2atoms/A...
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