FinalW08Solution - CEE 379 Final Exam Solution Winter 2008...

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Unformatted text preview: CEE 379 Final Exam Solution Winter 2008 Name: HW Total: Open notes. Part I: Short Answer 1. For the simple truss shown, member b ’s temperature increases and so its length increases. Draw arrows to show the orientation of the equivalent misfit loads that would be used to analyze the structural response. (3 pts) 2 3 4 1 a c b d e 2. The frame element below has the stiffness matrix shown (assume consistent units throughout, and assume also that our standard degree-of-freedom numbering for frames is used). 1 2 [ k ] = 929 . 96- 615 . 85 371 . 22- 929 . 96 615 . 85 371 . 22- 615 . 85 416 . 75 556 . 83 615 . 85- 416 . 75 556 . 83 371 . 22 556 . 83 96 , 518- 371 . 22- 556 . 83 48 , 259- 929 . 96 615 . 85- 371 . 22 929 . 96- 615 . 85- 371 . 22 615 . 85- 416 . 75- 556 . 83- 615 . 85 416 . 75- 556 . 83 371 . 22 556 . 83 48 , 259- 371 . 22- 556 . 83 96 , 518 (a) What would the system moment be at Joint 1 due to a unit vertical displacement at Joint 2? (3 pts)-556.83 (b) What would the system moment be at Joint 2 due to a unit rotation at Joint 1? (3 pts) 48,259 3. The beam shown below has an internal hinge at Joint 2, and the corresponding stiffness is given. Indicate the changes necessary so that the given stiffness matrix includes the effects of the addition of a rotational spring, k R , across the hinge at joint 2....
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FinalW08Solution - CEE 379 Final Exam Solution Winter 2008...

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