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Electrical Engineering 122 - Spring 1997 - Edell - Midterm 2

# Electrical Engineering 122 - Spring 1997 - Edell - Midterm...

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EE 122, Midterm #2, Spring 1997 EE 122, Spring 1997 Midterm #2 Professor Edell Problem #1 In this problem you are to select which of the multiple choices are most correct or most appropriate. Please circle the appropriate roman numeral to indicate your selection. Then you are to explain why your selection is most correct/appropriate. Approximately 1/5 credit is given for the "choice" and 4/5 for the explanation. A) (5 points) A BCH code with a minimum distance between codewords of 7 may be used to i. detect up to 7 errors (per block). ii. correct up to 4 errors (per block). iii. correct up to 3 errors (per block). iv. correct up to 2 errors and detect up to 5 errors (per block). v. none of the above. Explain why: B) (5 points) ATM cells are 53 bytes long because i. the 48 byte payload is just large enough for an IP+TCP header. ii. the ATM designers patented a fast divide-by-53 algorithm. iii. small cells mean low latency for low data rate CBR applications. iv. 53 byte cells, together with 11 bytes of overhead, fit nicely (i.e. with little additional overhead) into a DS-1 frame. v. none of the above. Explain why: C) (5 points) TCP uses a combination of GBN & SRP. Therefore, TCP is rather complicated. It is file:///C|/Documents%20and%20Settings/Jason%20Raft. ..%20-%20Spring%201997%20-%20Edell%20-%20Mid%202.htm (1 of 8)1/27/2007 4:25:17 PM

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EE 122, Midterm #2, Spring 1997 possible to design a simpler transport layer (i.e. end-to-end on top of IP that uses ABP? i. True. ii. False. Explain why: D) (5 points) Statistically multiplexing 24 constant bit-rate channels will result in a statistical multiplexing gain of approximately i. 2.4 ii. 1.2 iii. 1.0 iv. 0.75 v. None of the above. Explain why:
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Electrical Engineering 122 - Spring 1997 - Edell - Midterm...

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