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FT_SS02_2008

# FT_SS02_2008 - Fate Transport Solution Set#2 CE/ESR 479/579...

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Fate & Transport CE/ESR 479/579 Solution Set #2 1. Chapter 1, Problem 17 I convert everything to ug, m, and s units: Q = 200 gpm - 756 L/min = 12.6 L/s V = 1.5e06 gal = 5.67e06 L d = 10 ft/3.25 ft/m = 3.08 m A s = V/d = (5670 m 3 )(3.08 m) = 1843 m 2 MW = 133 ug/umol Mass balance: Inflows of TCA = Outflows of TCS and than solve for C w , concentration in the waste: Q C m m Q C in w vol bio out = + + max C gcm s m cm m mol L d L g mol d s L s g s L s w = + + ( )( )( ) ( )( . )( )( / , ) ( . )( ) / ( . ) 3 10 1843 10 6 10 567 10 133 1 86 400 12 6 10 12 6 4 2 1 2 4 2 2 3 1 1 6 1 1 1 1 x x x µ µ µ µ µ C w = 450 ug/L 2. Chapter 2, Problem 1 [3 pts total] a) [1 pts] The peak of the salt pulse travels at the mean velocity of the stream. It looks like peak arrives 20 m downstream (the samploing point) after about 750 s. V = 20 m / 750 s = 0.027 m/s = 2.7 cm/s (a rather sluggish stream) b) [2 pts] The curve is NOT expected to be exactly Gaussian because this time-series data rather than the spatial distribution. The clous of salt continues to expand as it passes the

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FT_SS02_2008 - Fate Transport Solution Set#2 CE/ESR 479/579...

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