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Unformatted text preview: mitchell (jm56986) HW #5 montgomery (24131) 1 This printout should have 20 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 3) 10.0 points Two 4.6 g bullets are fired with speeds of 35.9 m/s and 61.7 m/s, respectively. a) What is the kinetic energy of the first bullet? Correct answer: 2 . 96426 J. Explanation: Basic Concept: K = 1 2 mv 2 Given: m 1 = 4 . 6 g v 1 = 35 . 9 m / s Solution: The kinetic energy of the first bullet is K 1 = 1 2 m 1 v 2 1 = 1 2 (4 . 6 g)(35 . 9 m / s) 2 1 kg 1000 g = 2 . 96426 J 002 (part 2 of 3) 10.0 points b) What is the kinetic energy of the second bullet? Correct answer: 8 . 75585 J. Explanation: Given: m 2 = 4 . 6 g v 2 = 61 . 7 m / s Solution: The kinetic energy of the sec ond bullet is K 2 = 1 2 m 2 v 2 2 = 1 2 (4 . 6 g)(61 . 7 m / s) 2 1 kg 1000 g = 8 . 75585 J 003 (part 3 of 3) 10.0 points c) What is the ratio K 2 K 1 of their kinetic ener gies? Correct answer: 2 . 9538. Explanation: Solution: The ratio of the two kinetic energies is K 2 K 1 = 8 . 75585 J 2 . 96426 J = 2 . 9538 004 10.0 points If you exert a force of 16 N to lift a box a distance of 1 . 86 m, how much work do you do? Correct answer: 29 . 76 J. Explanation: Work is W = F d = (16 N) (1 . 86 m) = 29 . 76 J 005 10.0 points A student wearing frictionless inline skates on a horizontal surface is pushed by a friend with a constant force of 46 N. How far must the student be pushed, start ing from rest, so that her final kinetic energy is 351 J ? Correct answer: 7 . 63043 m....
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 Fall '09
 montogomery
 Physics

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