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Unformatted text preview: not have any poles outside the unit circle. a) The given z-transform has a pole at infinity. Therefore, it is not causal. b) The poles of this z-transform are at z = 1/4 and -3/4. Therefore, it is causal. 4. a) y [ n ] = x [ n-1] b) Y ( z ) = X ( z ) / z . Hence H ( z ) = 1/ z . The ROC is all z except zero. c) It is stable because the ROC of its transfer function includes the unit circle. d) Inverse system: H ( z ) = z ....
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- Spring '09