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part16

# part16 - Probability Homework Solution#5 3.13 1 P A = P X >...

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1 Probability Homework Solution #5 3.13 () 1 [] 0 3 1 1 ( 1 ) 3 12 4 4 2 1 1 1 6 1 1 33 3 3 3 2 7 2 7 ( 0 ) ( 0 )1 XX X PA P X PB P X PX PC P X F F PD F ⎛⎞ => = ⎜⎟ ⎝⎠ =≥ = = = =− < = < < = = = =< = = 3.14 (a) X is a random variable of mixed type since it is continuous except for discontinuity at 0 and at 1. (b)

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2 3.16 3.21
3 3.27 () [ ] ( ) | [] 0, , 1( ) (1 ) ) , 1 ) 1, , X XX X xt t t PX x X t FxXt PX t Fx Ft Ft ee e x t ex t e λλ λ −− ≤∩ > >= > < = < =

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part16 - Probability Homework Solution#5 3.13 1 P A = P X >...

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