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Unformatted text preview: The Sixene Pokemons problem (back of page 5 of the exam handout). a. 1/4 of the progeny will accumulate Onene. b. 3/64 of the progeny will accumulate Twoene. To get this answer, look at the phenotypic ratios expected from the cross of AaBbCc x AaBbCc. The bbcc progeny will accumulate twoene provided they are A-. bbcc progeny are 1/16 of the total, and then subtract out the quarter of them that are also aa (ie 1/16 - 1/64 = 3/64). Another way is to calculate initially the ratios for all three genes. These are 27:9:9:9:3:3:3:1 (hint: the algebraic product of 9:3:3:1 x 3:1). Assign phenotypes to each fraction. One of 3/64 fraction is A-bbcc. c. The answer depends on your interpretation of the biochemistry in the problem. If you assume, as I do, that either Fourene or Fiveene can be converted to Sixene under the influence of the E gene product,...
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This note was uploaded on 11/30/2009 for the course LS 4 taught by Professor Ribaya during the Fall '08 term at UCLA.
- Fall '08