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# P213E1F09ans0001-1 - 7 PHY 213 Exam#1 Prof J Rolllno lg...

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Unformatted text preview: . 7; PHY 213 Exam #1 Prof. J. Rolllno _. lg 10f909 ‘ /3 052 x /C}rﬂ45 y M J 1) A. 150 kgirm3 = a 16 O gimma' "hi-3 "'- 3 arm.“ 6 (EL/Mg Zibﬂxéefj ,«o‘m’o‘ B. 250kmihr= - )‘ omis. M géom I‘m“ C. A ﬁctitious formula that could relate “blinks” ( b ), to “winks”,( w ). is: b = am2 + c iog(dw2) ' 2'- ' -- L What are the units for 'a' ? t) W ‘c'? E 'd'? M," (10) 2) A particle moves along the x-axis according to the following equation. ‘x' is in meters and 't’ is measured in seconds. x = 2.50 t3 - 4.5m2 a. Determine the formula for the instantaneous velocity for this particle. W761} “.— ¥.5‘0t1~'—900f cit b. Determine the formula for the instantaneous acceleration for this particle. at:- A.»— .. moat—WM ﬁ 0. Calculate the average velocity for the interval t=1.0 to t=3.0 seconds. ' ..__ ‘ .—.\ M [-1 if .S‘ 5(0) 2.5‘0 (3)3—- 9.40 (UL ‘1 \$9 ‘* 3,42:- xcn = 2.54:)" -' t“ H) (161.2: :1. Calculate the avegge acceleration for the interval t=1.0 to t = 3.0 seconds. 0-! r Cs __ ‘ “(5) ' 5,24,! 4: 2f. (Hui/[1 - L- \ L: *M 29.0) - 6/0) we Au» 2w 912.0 e. Calculate at what times(t) the particle will be at x = 0.0 meters. 0 : 9?.5‘izg‘- V4371 0 ‘- f Y. f-s'vf - 54m) (15) 3) A car accelerates at a(t) = 3.0012 -2.00t from rest. a. Caicuiatgithe particle's veffity at the end of 2.00 seconds. .='W=£?t1—zb#: its—(1 7 +004; 0 b. Determine the displacement from the original pzo'sition. ' 1: Qt .wﬁf’.t‘m 111.19 \$255;- £33m __.—— ‘r 5 3 o U (10) 4) Assume you're standing on a ledge 50.0 meters above the ground and you drop a bail. 1.00 seconds later your friend VOJ throws a ball straight down at 20.0 mis. Which ball hits the ground ﬁrst? How much time elapses between the hits. “300 = Amt: 1=fue’"—’b?:3 = -*t."tt‘-_20£’ "9-911—Mrrr- c) T ‘t “gilt-201': -5‘c- = c) 3 lqv I] 2‘74 1 -20 J: 401') -~Ct‘n‘!)(9)('i3) 1.2%.!qu ‘61— ("II FUEL/D (1ou ‘ ~70 4 9/001- 190 £qu 0 CL? ‘1' a, y o ﬂ -—2.0H + 34‘? {-7575 (10) GHQ 7‘ "H 6‘0 H o 5) Suppose you walk the fotlowing two paths: 150 meters @ 12 ° and 100 meters Q 225°; but your tﬁend walks 100 meters @ 30° and 150m @270. Knowing that you both started from the 3 me position. how fangnd in what at ' should you walk to meet her? - K; —.——> m 100 w 30?} + loo .0» 30‘? #50 an 2%? + W01” 29?”? __ C4.) SIG ﬂ__ #2327} Ii‘rﬁ'ﬁ (9 ~ ’" NEE-r ——/5""7':}' .- '1, M55”: t, (23235)?" U‘I’JB (1o) Consider the vectors: A=2i-j-4k and B=-2j+5k Calculate: a.AoB= 2 '—I ‘37 A __ O 2 #2e I13- 3A= .__’2_:|: +— g/ﬁ‘ A /\ A _QQ+3§+ALK ~-»5?+J+’7“ H c.AXB= A A /‘ 10A #4 (4“- ?) An.€*"‘3‘-* J K d. the angle between A and B Q 4| ___.._‘ _:4 - ‘: CJ‘S C" COKE) 2' ' \J—Z—T 2 1 A B . <0 : {36.9 (“QTQL/i-Iéf-I fur-27 I3 whim =‘ (a? (20) When a certain softball player throws a softbaliwith an initial angle of 60°. the ball reaches herteammate 30.0 meters away. Her teammate catches the bail at the same height as it was reieased. For how many seconds was the ball in theair‘? "1 . t roan-«o Raﬁ/{:11}; 26;“ (43 at) : Zliﬁd lg .2 I 0 ' - ' 65-. _ 91"? (30) 7.2)(“3 ) 0 git} (20" ‘ &= 32¢; (m h ‘- g’Y’m m0 2 j’& 3) 9) If a highway exit has a radius of 65.0 meters and the great acceleration the tire can produce on a wet road is 5.00 ml's2 , what is the fastest speed a car can exit without skidding? Q T 40:} {q . -‘ . _- __._.. /r 0'1 i/LP‘SMCK/i ‘3 1‘5-o0>(“’£°) S: (5) A pilot wishes to fly with a heading of 115° at 150 rnfs. The prevailing wind is blowing at 20.0 ms at direction of 300°. With what air velocity must she ﬂy? Give the magnitude and direction. These are lab coordinates. Give your answer in lab oomdinates. '-._——I- H “’1‘ ~23 P/é ’ N/‘TM “4* iii/c. [Lg/.42 : Wm _" ACE/c >< N34 : A514 mm:— zowem“ : _ 435‘} ' x _ (10) ﬂ “lg/4 j t w 0 u \ “‘1 W Lu J F‘k *LJ \J“ u v.5) x.../ ‘V \.+ /—._ "‘--.. L,3 w A). U r» ll \u. “kl C) C) m; ...
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## This note was uploaded on 11/30/2009 for the course 750 203 taught by Professor Croft during the Spring '08 term at Rutgers.

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P213E1F09ans0001-1 - 7 PHY 213 Exam#1 Prof J Rolllno lg...

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