2.3 - MATH321 HOMEWORK SOLUTIONS HOMEWORK #4 Section 2.3:...

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Unformatted text preview: MATH321 HOMEWORK SOLUTIONS HOMEWORK #4 Section 2.3: Problems 1, 2(b), 3, 4(a)(c), 9, 11, 12, 13 Krzysztof Galicki Problem 2.3.1 (See Answers to Selected Exercises ). Problem 2.3.2 (a) A (2 B + 3 C ) = parenleftbigg 1 3 2 1 parenrightbiggparenleftbigg 2 parenleftbigg 1 3 4 1 2 parenrightbigg + 3 parenleftbigg 1 1 4 1 2 parenrightbiggparenrightbigg = = parenleftbigg 1 3 2 1 parenrightbiggparenleftbigg 5 3 6 5 4 4 parenrightbigg = parenleftbigg 20 9 18 5 10 8 parenrightbigg . ( AB ) D = parenleftbiggparenleftbigg 1 3 2 1 parenrightbiggparenleftbigg 1 3 4 1 2 parenrightbiggparenrightbigg 2 2 3 = = parenleftbigg 13 3 3 2 1 8 parenrightbigg 2 2 3 = parenleftbigg 29 26 parenrightbigg . ( AB ) D = parenleftbigg 1 3 2 1 parenrightbiggparenleftbiggparenleftbigg 1 3 4 1 2 parenrightbigg 2 2 3 parenrightbigg = = parenleftbigg 1 3 2 1 parenrightbiggparenleftbigg 7 12 parenrightbigg = parenleftbigg 29 26 parenrightbigg . (b) A t = parenleftbigg 2 3 4 5 1 2 parenrightbigg A t B = parenleftbigg 2 3 4 5 1 2 parenrightbigg 3 2 1 1 4 5 5 3 = parenleftbigg 23 19 26 1 10 parenrightbigg . BC t = 3 2 1 1 4 5 5 3 4 3 = 12 16 29 . CB = ( 4 3 ) 3 2 1 1 4 5 5 3 = ( 27 7 9 ) . CA = ( 4 3 ) 2 5 3 1 4 2 = ( 20 26 ) ....
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2.3 - MATH321 HOMEWORK SOLUTIONS HOMEWORK #4 Section 2.3:...

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