Week6-3 - Assignment Assignment#6 Forsubmission 8.16 8.22 Forpractice 8.17 8.36 8.50 8.45 DueTuesday,March3rd at12noon Beam BeamDesignExample

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ssignment #6 Assignment #6 For submission .16 .22 .50 8.16 8.22 8.50 For practice 8.17 8.36 8.45 TdMh 3 t 12 Due Tuesday, March 3 rd at 12 noon
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eam Design Example Beam Design Example W18 × 35, S = 57.6 in³ W16 × 31, S = 47.2 in³ 14 2 S 29 0 in³ W14 × 22, S = 29.0 in³ W12 × 26, S = 33.4 in³ W10 × 30, S = 32.4 in³ W8 × 40, S = 35.5 in³ t il ill b ht t Most economical will be lightest. W14 × 22 Wide flange beam, 14 inches deep, 22 lb/ft
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eams of two materials Beams of two materials
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exure Formula Flexure Formula x y M = σ Stress in a beam produced y a bending moment z I by a bending moment This relationship assumes that the beam is homogeneous. For a beam with two materials (two different elastic modulli) the relationship will have to be modified.
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ansformed ction Method Transformed Section Method Transform the two component beam into an equivalent beam that as only one material has only one material. The flexure formula would apply to e transformed shape the transformed shape.
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ansform to equivalent beam? Transform to equivalent beam? The transformed cross section must yield the same bending strains as the actual cross ction section. y rain ρ ε x = Strain
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ansform to equivalent beam? Transform to equivalent beam?
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This note was uploaded on 12/01/2009 for the course CIVE 207 taught by Professor Shao during the Winter '09 term at McGill.

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Week6-3 - Assignment Assignment#6 Forsubmission 8.16 8.22 Forpractice 8.17 8.36 8.50 8.45 DueTuesday,March3rd at12noon Beam BeamDesignExample

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