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# Homework - t Value Pr> |t| 95 Confidence Limits Intercept...

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Sasha Vaziri STA 4210 HW 1.19 a) y = 2.114 + 0.0388x y= GPA; x= ACT score bo = 2.114 b1 = 0.0388 b) Yes the estimated regression function appears to fit the data well. c) A student with an ACT score of 30 will have a GPA of approximately 3.2 d) A point estimate of mean response when test score increases by one point is 0.0388

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1.20 a) Estimated regression function is y= -0.5802 + 15.035x b) c) b o does not provide any relevant information in this model. This is due to the fact that b o is irrelevant because there needs to be a minimum of one phone call in order to work a certain number of minutes and due to the fact that we cannot have negative time or minutes. d) When X=5 a point estimate of Y is 74.6 2.4 a) Parameter Estimates Parameter Standard Variable DF Estimate Error t Value Pr > |t| 99% Confidence Limits Intercept 1 2.11405 0.32089 6.59 <.0001 act 1 0.03883 0.01277 3.04 0.0029
b) c)

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2.13 a) Parameter Standard Variable DF Estimate Error t Value
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Unformatted text preview: t Value Pr > |t| 95% Confidence Limits Intercept 1 2.11405 0.32089 6.59 <.0001 1.47859 2.74951 act 1 0.03883 0.01277 3.04 0.0029 0.01353 0.06412 Dependent Predicted Std Error Obs Variable Value Mean Predict 95% CL Mean 95% CL Predict Residual 3 3.7780 3.2012 0.0706 3.0614 3.3410 1.9594 4.4431 0.5768 25 3.5560 3.2012 0.0706 3.0614 3.3410 1.9594 4.4431 0.3548 b) c) The prediction interval is wider than the confidence interval because the prediction interval introduces two sources of variances whereas the prediction interval only introduces one source of variance. Therefore the prediction interval should be wider than our confidence interval. 2.23 Analysis of Variance Sum of Mean Source DF Squares Square F Value Pr > F Model 1 3.58785 3.58785 9.24 0.0029 Error 118 45.81761 0.38828 Corrected Total 119 49.40545 Root MSE 0.62313 R-Square 0.0726 Dependent Mean 3.07405 Adj R-Sq 0.0648 Coeff Var 20.27049...
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