hw4 - ActivPhysics can help with these problems: Activities...

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ActivPhysics can help with these problems: Activities 15.1, 15.2 Section 35-2: Reflection Problem 1. Through what angle should you rotate a mirror in order that a reflected ray rotate through 30°? Solution Since el = 0; for specular reflection, (Equation 35-1) a reflected ray is deviated by 4 = 180° - 24 from the incident direction. If rotating the mirror changes 81 by hel, then the reflected ray is deviated by A4 = 1-2AQ1( or twice this amount. Thus, if A$ = 30°, lAO1l = 15". Problem 1 Solution. Problem 2. The mirrors in Fig. 35-33 make a 60" angle; A light ray enters parallel to the symmetry axis, as shown. (a) How many reflections does it make? (b) Where and in what direction does it exit the mirror system? FIGURE 35-33 Problem 2 Solution. . - Solution The first reflected ray leaves the upper mirror at a grazing angle of 30°, and therefore strikes the lower mirror normally. It is then reflected twice more in retracing its path in the opposite direction. Sec3on 35-3: Refraction Problem 8. In which substance in Table 35-1 does the speed of . light have the value 2.292~ lo8 m/s? Solution 11. A light ray propagates in a transparent materid at 15O to the normal to the surface. When it - -- emerges into the surrounding air, it makes a - 24" angle with the normal. What is the refractive index of the material? Solution Snell's law (Equation 35-3), with air as medium 1, gives nz = nlsinBl/sin02 = lx sin24O/sin 15' = 1.57. ---- ~-
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hw4 - ActivPhysics can help with these problems: Activities...

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