CHMoctober2003 midterm

CHMoctober2003 midterm - .. . . - _ Student Numberguwh‘ '...

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Unformatted text preview: .. . . - _ Student Numberguwh‘ ' PLEASEVPRINT CLEARLY ' “CHNIHOYéwheennth 'October 27, 2003 -‘ 1 Hour . AnSWer all questions, 25 marks per'question. The only aids allowedare non-prografrun'able calcutators. l. I a. - Onlthe Periodic Table below, fill-in the chemical symhots for _as many-elements “as - .you cart. Label the Groups of the Table with the values of the n and 1 quantum ‘ numbers of the outermost electrons of the elements in the Groups. l). - Threeflelem-ents heve the following electron configuratioiis: __ h%%%m“ .. wwww~ lflflflflwi' The first ionization energies of these elements (but not necessarily in the same order) .‘ are 0.419, 0.735 and,t.52'l-_MJ mot-l. The atomic radii ofthese elementsfilso not _ “neCessa-trily in the same order) are 160, 98 and 235 pm. Idehtify the three'ele'ments ' " hand match the apfiropririte values oiionization energy andd'atorrii'c radiusto’each - n, " electron configuration. A t _. I ma i '- Elem??? . r qlqmit rim-ClI‘US'“ I 1 s 2' " r - r ' x _ ‘ ‘ l57-ZS‘ 35.3};5 I. V ' ‘ It Arid/WV V I_ 2 6 2 I 2'" " ‘ Ilstzsz'gp'ag ‘ " M8 ' C’I‘rasMII/me/ ' " ‘ .isol'pLQV/‘H - _. , ' r . , '- ' m '_ I‘" ' 7 . H' ' "'lS'VSt-zpék’fir‘es‘ li- " .. t CLLHCl Mjfi/ ‘- 235" .I‘ '2. 'l ‘ a. For each of the following iiioleCulesor complex ions (for which the underlined atom I ' ' ' is the central atom), -- A_ ' - - ‘ (1) " ‘ classify aceordiiig to'the'AXE nomenclature of theVSEPR theory and (2) firm the three-dimensional structure, showing all valence shell electrons of 'all atoms 'and assigning any formal chargef ‘ Dimensional I Diagram . , N: 5" 7+3‘30 A ‘0i6,.)2(o) = 5" ‘ «21.27 «sam- ‘74217133 _ cm: a ' 5w : 3 ‘ 5+lzr? :2‘r' - ‘6 h H‘ = l: : jig-"l Pnh‘s S C' 5 Mrs vb, _ Define concisely, in one or twu sentences, each of the following termszl (I) 'HeiSenb‘eré UncertaiptyPrineiple ' / . It - ‘ i: -’S {mm-Sng mmsuw' RH“ H'e Possjbfl anal velocitfl 1' or 0‘" (E'Teciimnl PreC-FSEIJ a}. a “Mme” '1" firm: We more Precise .the 'm noénl- “ml? 0 e, l ' b _' I r I ensure r n Hne . less :pregga H“? Méqsurewm‘ OF "ranch—q ‘ (2y ' palm Exclusion Princip_l_e...-' -‘ we; 11M," 945::th the same atom CM, huvé 54w 9.1} op' amp} humbers (n £ m . r I . r - - ' ‘ r _ M A0107 g sample of a compound which was Immun- to contain only carbon, hydrogen I ' and oxygen wag burned in excess oxygen. The products of the combustion were ' compound? ‘ ' '1'5063 052', [firmly 1.606 g of co: and 9.659 g of H20. What is the empirical ‘fon'nula of the Atofiiic Masses (g/mol): H= 1.01, c ‘= 12.01, 0: 16.00 _ coho: + a1 ‘axCog'nyzo c.7073 _ 1.5053_ZG.65'13 .z/ . ' . ~‘-‘- COL ‘ ‘z/ 0.0.355: ml; 5._——4———_—_, ‘ .V-mfl-I_ ill: orwacl 0‘3qu “2‘3 x. ‘I l m [ lrz' ' fl, 7 h ‘ l a. no H, r.___. .t ‘ "'"—' ‘ ———-—— = o. tr;ng x : t v ’33 l WW”,- 7, ° '5“le * 0‘ , $732 3 H I 0.707 C I _6/ _ ' ‘ . ' 3 ’Hbo‘V ' “5359-0-075231t: o. I‘M/3'30 1 mol _ x :jo. [274%,]:I Ck .-' -- ' - . I 0'0“? MatsrC ‘ j ' H - ‘ V , V/D-Olz’a —' 3 _ 090732;“ g .. - . A ‘ aofilzz’ -‘ 6 ' 0.0lzz -M°}5y..lcr ‘ ' Clot-z; _. 1 _ {,2 V ‘FbleSOt-i PbSOH +K+W 'Xl, ' c plow 14’ PM P5532 + ZH-zs I (1) -_ Balance the following reaction which occurs in aqueous, basic solution. ’l‘ See back of “‘{5 Priij please}, 3W0 I "madam Sci/Vol; + 2( Hc)‘ r ‘ {2) Balance the following reaction which occurs in aqueous, acidic solution. ‘H am) Hi «(-21. .?' . 1‘2 - Pb’ + P1302 “+4 HISO¢ —» Pbso4'.+ H10: 2309?? P5509 *z‘tHiO 0H A‘?‘2'F535H + 292:2. Vi; ._ ' z. x 0" N lém‘w v} n-Ifoqlfféév Mt rye/xxx '27 ' Hydrogen cyanide is produced industrially fromthe reaction df'gaseous amdnia, oxygen « and methgne: _ ' ' ' A ‘- 021511-13 +_302‘+_2CH‘ _—>‘ mew-5611110. a. I Draw the Lewis structure of each of the reactants ahd products. fl; 9;; (2 9g 3; H _ ' ~ ' .. n ' if? AI/r 030-“ H-C.1—-H H / \_HV I _ I H 13;. ‘ moo x 103 kg of each ofNHJ, 02 afid CH4 are reaeteci, wha't mass deCNwill be produced, assuming 100% yield? . '_ I " Atornic Massas (g/mol): H =T 1.01, C = 12.01, N '=_I14.01, O = 16.00 . 5x103 I43 Mg x lmbl 2W“? ‘ -- (SXIo§3)'_ lvs _ . (/5? M“ N'H/z = IHWGS"8.83 A 6x103 K3 02-131 0.: r " I ' . Q' ' . ’ ‘ = -m . I" .‘+ _ 7 _ .523 _)Séz:O.oo log/3 ; 52033;; "7‘ _ x0 1 ywi L—L; 312503.00“: CH “39"- / y [/2 z GO Ifiézfceo MIA-0'2- X' 2 man we»? ' 2— Mammy: - H'CIV ...
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CHMoctober2003 midterm - .. . . - _ Student Numberguwh‘ '...

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