Untitled - small ((1/3) 2 ) Sierpinski Carpets area (A...

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A 0 = 2 2 = 4 A n = 8·(1/3) 2 ·(A n-1) = (8/9)·(A n-1) It says that "sierpcarpet 0" has area 4, and that the area of "sierpcarpet n" (A n) is the same as all the (8)
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Unformatted text preview: small ((1/3) 2 ) Sierpinski Carpets area (A n-1). From this you can derive that: A n = (8/9) n 4...
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This note was uploaded on 12/03/2009 for the course IAS 2045 taught by Professor Kent during the Spring '09 term at Arkansas State.

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