1e3formula - Constants and Formulæ: Earth’s...

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Unformatted text preview: Constants and Formulæ: Earth’s gravitational field: g = 9.81m/s 2 permittivity of vacuum: 0 = 8.85 × 10−12 C2 · N−1 · m−2 Coulomb’s Law constant: ke = 1/4π 0 = 8.99 × 109 N · m2/C2 permeability of vacuum: µ0 = 4π × 10−7 T · m/A speed of light: c = 2.998 × 108 m/s electronic charge: e = 1.602 × 10−19 C electron mass: me = 9.11 × 10−31 kg proton mass: mp = 1.67 × 10−27 kg vx = v0x + ax t 1 x = x0 + v0x t + 2 ax t2 v2 r 1 K = 2 mv 2 ar = ke q1 q2 ˆ F= r r2 F = q0 E ke q r E= 2 ˆ r σ = 2πke σ infinite plane: |E| = 20 ΦE ≡ ΦE = E · dA ΦB ≡ Qenclosed 0 V = IR, P =VI −t/τ I (t) = I0 e or I (t) = If (1 − e−t/τ ) τ = RC or τ = L/R FB = q v × B FB = I ds × B τ (loop) = I A × B = µ × B µ0 I ds × ˆ r dB = 2 4π r µ0 I straight wire: B = 2πr N solenoid: B = µ0 I B · ds = µ0 Ienc dΦB , E =B v dt L ≡ N ΦB /I dI E = −L dt 1 U = 2 LI 2 2π ω = 2πf = , k = 2π/λ T y = A sin(kx ± ωt − φ) ω v = fλ = k E =− v= FT /µ ∆r λ d sin θ = mλ ∆φ = 2π a+b a−b ) sin( ) 2 2 a−b a+b cos a + cos b = 2 cos( ) cos( ) 2 2 4 sphere: A = 4πr 2 , V = 3 πr 3 cylinder: A = 2πr 2 + 2πrL, V = πr 2 L sin a + sin b = 2 cos( B · dA = 4πke Qenclosed σ 0 conductor: |E| = ∆V = = 4πke σ B ∆U E · ds =− q0 A ke q V= r ke dq V= r q1 q2 U = ke r Q A A C≡ =0 = ∆V d 4πke d 2 Q U= 2C − − − −1 Cseries = C1 1 + C2 1 + C3 1 + · · · Cparallel = C1 + C2 + C3 + · · · −1 − − − Rparallel = R1 1 + R2 1 + R3 1 + · · · Rseries = R1 + R2 + R3 + · · · I = nqvd = σE J= Area 1 RA resistivity ρ = = σ ...
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This note was uploaded on 12/03/2009 for the course CHEMISTRY 1E03 taught by Professor Britz during the Spring '09 term at McMaster University.

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