answerkeyquiz_7topost - depends on how well they explain...

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Question 1. Correct answer : (5 pts.) cAMP. Also acceptable is lactose and CAP Question 2. Correct answers: (5pts) The ribosome binding site in front of the β subunit is much stronger than the one in front of the α subunit thus much more β gets synthesized. Also acceptable is that the α subunit gets degraded faster than the β subunit. Other answers : (various pts) (5pts) The secondary structure of the mRNA is such that there are more/stronger binding sites for the ribosome (4pts ) A number of students said that the ribosome binding site is stronger for β than α so “transcription” is more efficient. I think this was just a minor mistake (3-5pts) There is some repressor that binds in front of the mRNA α subunit so that it’s translation is inhibited. Some try to relate this to the lac operon in that there is a repressor protein in front of the α subunit and not the β and that there is a signal that is required to remove the repressor protein to get the a subunit made. The number of points awarded
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Unformatted text preview: depends on how well they explain it. (3pts) The lifespan of the mRNA is short so translation of the subunit occurs but the mRNA starts degrading before enough can be made (2pts) The difference can be explained because the toxin is in a 1:5 ratio so the function of is much more necessary than the function of (2pts) The ratio of the subunits is 1:5 because it takes 5 subunits and 1 to create the toxin (2pts) A combination of mentioning that has more active binding sites and this somehow relates to the secondary strucure of mRNA and more/less activity. They fail to mention if they are talking about transcription/translation and if they mean ribosome binding sites. (0pt) Focusing primarily on trancription of the lac operon and how it relates to cholera in a way I cant understand. . Some also say that the subunit IS lacI and the IS lacy. I dont know what they are getting at...
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answerkeyquiz_7topost - depends on how well they explain...

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