Homework_7_Solutions - 9.34 a. 25 . 200 / 50 = = p . b....

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Homework 7 Solutions 9.1 a. Statistic because it is a sample value. b. Parameter because it is a population value. c. Statistic because it is a sample value d. Parameter because it is a population value (errors in the entire manuscript). 9.6 a. Statistics. The means are summaries for samples of 100 males and 100 females taken from a larger population. b. The sample means alone do not provide enough information to say whether the mean salary for males in the company is higher than the mean salary for females. It might be that the observed difference between sample means is consistent with the type of difference that could occur just by chance for any two randomly selected samples of n =100 taken from the same population. c. No, the sample means most likely would not be the same for two new samples. A sample mean varies from sample to sample.
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Unformatted text preview: 9.34 a. 25 . 200 / 50 = = p . b. 0306 . 200 ) 25 . 1 ( 25 . ) .( . = = p e s . c. 25 . 400 / 100 = = p ; 0217 . 400 ) 25 . 1 ( 25 . ) .( . = = p e s . 9.36 a. Mean = p = .2 b. s.d. ( ) p = 05 . 64 ) 2 . 1 ( 2 . = . c. .15 and .25, calculated as .2 .05. d. .10 and .30, calculated as .2 (2 .05). 9.57 a. Mean = population mean = 7.05 hours. b. 127 . 190 75 . 1 ) .( . = = = n x d s hours. c. .6.923 and 7.177, calculated as 7.05 ..127. d. 6.796 and 7.304, calculated as 7.05 (2 .127). 9.59 . 93 . 60 2 . 7 ) .( . = = = n s x e s 9.110 a. The population of possible net gains is highly skewed (not bell-shaped) and the sample size is small. b. The mean of the sampling distribution of x is the population mean = $0.35. The standard deviation of x is 10 67 . 29 $ = n = $9.38....
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This note was uploaded on 12/06/2009 for the course STAT 200 at Pennsylvania State University, University Park.

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