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Unformatted text preview: 9.34 a. 25 . 200 / 50 = = p . b. 0306 . 200 ) 25 . 1 ( 25 . ) .( . = = p e s . c. 25 . 400 / 100 = = p ; 0217 . 400 ) 25 . 1 ( 25 . ) .( . = = p e s . 9.36 a. Mean = p = .2 b. s.d. ( ) p = 05 . 64 ) 2 . 1 ( 2 . = . c. .15 and .25, calculated as .2 .05. d. .10 and .30, calculated as .2 (2 .05). 9.57 a. Mean = population mean = 7.05 hours. b. 127 . 190 75 . 1 ) .( . = = = n x d s hours. c. .6.923 and 7.177, calculated as 7.05 ..127. d. 6.796 and 7.304, calculated as 7.05 (2 .127). 9.59 . 93 . 60 2 . 7 ) .( . = = = n s x e s 9.110 a. The population of possible net gains is highly skewed (not bellshaped) and the sample size is small. b. The mean of the sampling distribution of x is the population mean = $0.35. The standard deviation of x is 10 67 . 29 $ = n = $9.38....
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This note was uploaded on 12/06/2009 for the course STAT 200 at Pennsylvania State University, University Park.
 '08
 BARROSO,JOAOR
 Statistics

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