W09_Mid2A_key

W09_Mid2A_key - EC 41, UCLA \Vinter 2009 Name (print)...

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Unformatted text preview: EC 41, UCLA \Vinter 2009 Name (print) Midterm #2 - Version A — 2/23/09 RE Ch 4,5, 6.1, 6.2 TA: Name & Section Time - The normal table and useful formulas are on the last page ot'this exam. - Only pens, pencils and erasers may be used. this is a closed book, Closed note, exam. - Students may use a calculator, but nothing that can access the internet. — Write non-integer answers to 3 significant digits, e.g., 333, or 3.33 or .0333 - This exam consists of 10 Trues’l-‘alse (20 points). l0 short answer (30 points) and 5 longer questions (50 points) — Clearly “I rite answers on this exam. No points are awarded for illegible ans“ ers. - Be prepared to Show a photo lD during the exam (6.9... UCLA lD) — You may leave when finished. Do not disrupt those still taking the exam. 1. Circle T fer True or F for False (2 points each) lflrF 2)To@ The primary benefit ofa well-diversified portfolio is that the standard de\ iation of its return will typically be less than that ofa less-diversified portfolio. lithe random variable Z = X-t-Y, then standard deviation of Z is the sum ofthe standard deviations of X and Y (o; ox + 5y) lfthe random variable Z = X-l-Y, then the variance of Z is the sum ofthe variances of X and Y (03-2 = 6;:2 6Y2) lftw'o events are disjoint, probability ofA or B probability ofA plus B —- PM) " P(B) Benford’s Law (used to cheek accuracy offinancial documents) implies that the probability ofthe lirst digit of numbers in financial documents is equally likely to be any integer from 1 to 9. lftvm assets hm e correlation “- - l. any portt'olio with of these tuo assets \\ ill hm e st';-tn(lard <ch iation - 0 A confidence inten'al gets wider (larger) as the number ofobservations in a sample is increased. For a particular calculated positive sample mean )7, the probability of rejecting a null hypothesis Iii-41:0, is smaller against a two-sided alternate Ha: u :t 0; than against a one-sided alternate H.._: it I‘ll. 10) T or@ In one calculates a 95% contidenee interval, 95% of the means ofa given population. it. are in this interval. 11. Briefly, clearly, and correctly answer the following 10 questions (3 pts. each) 1) Consider two independent events, A and B, where P(A) = .3 and P(B) = .2. a) What is the probability that A occurs given that B occurred = P(A l B)? ‘ = b) What is the probability of both A and B occur? Photo: NM—PtBJ: (av-2) c) What is the progahility that neither A nor B occur? : PM att‘mm firifir‘iili— pm)? -— [,[grz r.0{;i=t-.£/£[/ MM 8‘ 2) Consider the random variable X with the density curve below. a) What is the distrihution ofX is called? b) Suppose random variable Y has the same distribution as X. Dram the distribution ot‘Z — X + Y to the right: o) What is the probability that Z is greater than 1? P(Z> l)'-= 3) in upopulation ot' \xorkers, 20% earn $10 and 80% earn $20 per hour. a) What is the merage “age of \\0l'i\'Cl'.\' in this population? .ZODH r800) ’ 2 H6 [3) What is the population _\_'2n'izinee of the wage for these \x'orket's? GZ '201949J27l-9 tum“ = .2tglzttroth attorney 12mm. 0) What is the population standard deviation ofwage for these \x'm'kers? OWNED 4) Suppose the effect ofnn $800 Billion increase in government spending on GDP czm be written as n gemnetric series: 800.00 --I- 720.00 -- 648.00 : 583.20 -'.- 524.88 -.- (the sum of different "rounds" of autonomous spending) a) What prOpor 'on of each “round ofspending" is spent in the following round"? 9 b) Wt‘i[gimbomsatiies.;13.th€—-}3¥Q€l11C~I—O-f neonstztntt' -‘ sum of a geometric s ' " -‘*‘».«*"‘"'_ “mac; x"? 0 l 2 3 a; l Warming .3 2mm r 900 low i o) What is the total increase in GDP caused by the above increase in government spendi _ 5) Suppose a simple random odl]][)lC. si7e 36 is taken; the true population standnrd deviation. ._ is know to equal 4; but the true mean it is unknown: and the sample mean. X: 40. a) .-\ 959-1. COl'lllthllCC lI‘ltCl'VLtl for the sample mean is: ,—.._.. __ " i! (P + xiZ 1,} 2‘) Wilda—9%: Hula/36 b) lfl-ln: ll); = 39 and Hfi.’ In}; 3‘). the implied p—vnlnc is: I —~ [V : LS’ c) [fl-lg: tlx' = 39 and IL: ll); 1?: 30, the implied p-vnlue is: Puutw [l5 6) A random Vnt'inhle. Kean take (tn three. different values with the following probabilities: l_Va|ue__of_i: \ O 06154 '3 : ~36 2 0 IPrOPal-ftitity 0.6. 0—2.; 02'5 a) What is the mean of X? __ _ _ . . [bitoti‘16:2.4l b) What is the variance. ol~ _ c) What is the standard deviation ol‘ : t'ffi‘n 7') At Loon] State [TY lO“-"-'- ofthc students come. from each of ll) counties (all students come from one of these 10 counties} and assume the student pn'xpulzttion is mueh larger than size ot‘nny‘ sample size). Ltlé E [339W MV Pkwy—in n‘) lf‘twn ' 1 its me randnmly ohusen. What is the probability they are from the. same county? ()ka MW” 7 - 0 (“Fl P‘ c‘ Q“ I 3 N A \0} T 6“ l Cr uJ ,J r=\ N +- w l 9 (\I" 3; u ififirl'he followit'lg table is for a sample 0' anncs w 10 completed boot camp together White (W) Non-White (N W) Total: Sent to Iraq (5): 10 20 30 Not sent to Iraq (NS): 40 10 50 Total: 50 30 80 a) Find the following Conditional probabilities: 13(5an ; White) ’0 t ‘ Z_ P (Sent ' Not White) = 9) X and Y represent the return on two individual investments. 1.1.x = 2 ox = 3 My " 8 G -,- -- 4 Z '— a portfolio lialt‘invested in X and Y each, so Z = 5x + ,SY . Truc correlation between the returnsT pig-t- .2 a What i' th" m ‘an return of the ortfolio, ? s _, a > M ° P “2 .€[2J+.s[flt~ W!— b) What are the variance and the standard deviation ofthe return 0n the portfolio? “iii”: @1332 M5)2(HJ?+__2 (ZlCfi‘lé’JLsM/J FT is : 219+ H +i.z Gail/Ms : 272% 10) A deck of 52 cards has 13 hearts. _ a) What is the probability that a randomly drawn card will be a heat? '3 l 52 L t/ b) What is the probability that two eal'cls randomly drawn with replacement are both hearts? _____‘\ ..__ c) What is the probability that two cards randome drawn without ' u laconient are both hearts? III. Clearly answer the following questions. Show your work (10 points each, 50 total) 1) Suppose a simple random sample of size 64 is taken; the true population standard deviati o, is know to equal 9 but the true mean u is unknown; and the sample mean, if = 52. Si i 2_ 21) Find a 95% confidence interval for the mean value of X. 52 ‘l‘ 3/ 1,63? m Lani it 220‘)- 1 150;“ “(iii ‘- _ . What is the z-calculated titan b) Consider the Null Hypothesis, II;.: ll“: 50 observed sample mean X — 52? ; ism a go ' WT— “ ‘l/g‘lt7?) c) 1151' the previous problem, what is the *—eritical ’lien HU: .ui. = 5.0 ; H“: ‘11; .'> 50 and significance level, a = .05? ' (an: gulp 2} ( 'onsider 2 assets X; & X2 with the same expected return (1.1.1 = 112 = 10%) and standard deviation (0- h or. = 2%). YOU invest 50% in asset X; and 50% in asset X; a) What is the standard deviation oftlris portfolio when p = 0? p = .5? and p l? “i ’L 2 r 1 4— 22 D _ G. ‘ Z n it Hi (9‘0 0}: ’5. 2 ' 'l ‘ 2 p ' ll (31.? {it}; 1 + 1+ 269)§{2i.s’{2) = NH] = 3 (fiszlG) = 1» . — - HH : ~ _ p | Q, iiii'zm were 2 Li {Wm {29 h) Suppose one invests 25% in asset X1; 25% in asset X3; 259/0 in asset X3; and 25% in asset X4; true Inc-an ol‘all indii-‘idual investments X is p;._- r: 10% true standard deviation 01" all individual investments is ox - 2% and returns are uncorrelated, p = 0. What is the standard deviation ofthis portfolio? 'L . ’1» 2. .1 .. - 7— ._ GP sCzSS 224,629)? 71(25)22 ir[zsj? 22 —LIC?C‘J 22; Lips/2] c) Suppose one invests 10% in IO assetsjust like X] with true mean .ux— 10% true standard deviation ox ' 2% and all returns uncorrelated (p — 0). What is the standard deviation of this portfolio? G7: D(i_)72_ *LLai;2 445:: l6'32 P‘l’PZ’iol'I—s‘ 4' 3) Suppose the probability ofreceiving an order from any One particular sales call during a given period is exactly equal to .25 for (my sales call. What is the probability that: a) the first two sales calls result in x" .s a . .9. ‘ " 2 e no orders 67 ‘2)(3 ‘3‘) ‘ x 7 q ‘ /K _ one order JQ‘IS‘) l(2 {ll 1 Z (7 96.757 tnoorders? Z 0 ' . '2“ Z L [25 ,7s 61s} _ .23 b) the tirst three sales calls result in two orders? (2) [Zfizékf “— 3®le33rs> "' .Ile6’2s‘ 3: e) the first order is from the 41h sales call (so the first three calls do not result in orders)? {7§§7§)[7 s [29/ 0 4) For an auto insurance company, three outcomes are possible for any policy (measured in thousands of dollars) are: big loss -%8 '0 l i0“ Ia {1' small less -8 .04 -_ t q S? - :33 2. + I ,q 3 ill'vl'y‘fl no loss *2 .95 -_-_~ a) What is the expected net return from a policy on one driver, ELK)? it); What is the standard deviation ofthe return from a poliq on one dri\ er"? (7;; IQ: (find variance first) 1 ([1; .Bl (—qsaéil sputteatjz +9; (2‘16) _ ,_ . _ A I. “ _ L £17.22 4— 2.5158! +1.»?b2- 1020'! llwo b) It‘they have 10 customers what is the to r ' greet-Ito) expected net return from all 10 customers? rm : t O 6 w 0) Assume the outcomes ofdilTere-nt cuslmners are. independent. l’ind the standard {lcx'iution ofthe total aggregate. L as. [D t) {DLD.L{ _/ 70. ID m 5) a) At a given l‘uctory 10% ofthe thumb drives are defective. 10 thumb drives are. randomly chosen. Let X = number defective in this sample of 10. Use the binomial distributio to the probability that exactly one is defective in this sample. Ci ; _ Q ; (’Pltti'tn WW“ 0) Consider the factor} le)t)Ve where p = 10%. Suppose a sample of 100 drives is taken, Use the Normal approximation to the Binomial with continuitv correction to find the probability that i) 0 or fewer in the sample are defective; ii) 10 or fewer in the sample are defective; iii) exactly 10 are d Afective. - q S W ' Q’ 3 Z 5‘ = - ' "a 7 tiPVLP/b (I) wig—“ll ~ 169.» * l5) *‘lz =- ifi = l-.’“b7‘5 .\ : :3); 0‘ (it) {mat} ; 1369... <105j:i3é<wig“’” - péyt H' ...
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W09_Mid2A_key - EC 41, UCLA \Vinter 2009 Name (print)...

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