Chem 6A Quiz 2_key_Sect_E09_E04_E05

Chem 6A Quiz 2_key_Sect_E09_E04_E05 -...

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Unformatted text preview: QUIZ
2
E09/E04/E05
 Section
E____
 
 
 NAME
(Last,
First):
__________KEY________________
 Your
signature:
_____________________________
 Chemistry
6A
Fall
2008
 UCSD
PID:
|A|__|__|__|__|__|__|__|__|
 Total
Points:
_______
/
20
 
 
 
 You
have
10
minutes
to
complete
this
quiz.
Please
show
all
your
work,
but
write
the
 answers
in
the
designated
spaces.
The
points
allotted
for
each
question
are
indicated
in
 parenthesis.
 
 Potentially
Helpful
Constants:

 Potentially
Helpful
Equations:
 
 
 Mass
of
electron,
me
=
9.10938
x
10‐31
kg
 EK
=
½mv2
 Mass
of
proton,
mp
=
1.67262
x
10‐27
kg
 







 Mass
of
neutron,
mn
=
1.67493
x
10‐27
kg
 
 Fundamental
charge,
e
=
1.60218
x
10‐19
C
 c
=
νλ
 g
=
9.80665
m•s‐2
 8
m•s‐1
 E=
hν
 c
=
2.99792
x
10 λparticle
=
h(v)
 h
=
6.62608
x
10‐34
J•s
 Etot
=
Ek
+
EФ
 
 =
(1( 1))2−
1( 2))2)
 
 
 Potentially
Helpful
Conversion
Factors:
 1
J
=
1
N•m
 1
N
=
1
kg
m
s‐2
 1
L
=
103
cm3
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 Quiz
2
(10/13/2008)
Sections
E09
 1. 
 a) The
energy
required
to
eject
electrons
from
the
surface
of
a
metal
at
a
velocity
of
 _613_km/s
is
2.84x10‐22
KJ.

The
work
function
for
this
particular
metal
is
1.13x10‐ 19J.

(Show
Work)
(3pts)
 
 Units
conversion:

 
 
 
 2.84x10‐22
KJ
=
2.84x10‐19
J
 

 
 
 
 
 

 
 
 
 Etot
=
Ek
+
Eφ 
 

 

 
 
 
 
 
 
 








2.84x10‐19
J

=
Ek
+

1.13x10‐19J
 
 
 


Ek
=
1.71
*
10‐19
J
 
 
 
 
 
 
 
 
 
 
 
 
 
 EK
=
½mv2
 

1.71
*
10‐19
J
=
½(9.10939
*
10‐31)
v2
 
 
 V
=

21.71
∗
J9.10939
∗
10−31
 
 
 
 
 
 V=
613
*
103

or
613 
 
 
 
 b) 
Where
on
the
electromagnetic
spectrum
(as
in
to
which
type
of
light
does
this)
 does
this
radiation
correspond
to?
(Show
Work)
(3pts)
 
 
 
 
 c
=
νλ

 
 
 
 E=
hν
 
 
 
 
 
 
 λ 
 = 
 
ℎ E 
 
 
 
 
 
 
 
 
 

 λ
=
6.62608
x
10−34Js(2.99792
x

ms−12.84x10−19
J

 



=
700nm=
red
light/
visible
light
 2. T/F
(2pts
each)
 a) _F_
A
blackbody
object
absorbs/emits
only
one
particular
wavelength.

 
 
 b) _F_The
Schroedinger
equation
shows
us
we
cannot
know
the
location
and
the
 momentum
of
a
particle.
 c) _T_The
probability
density
is
zero
at
a
node.
 
 
 
 
 d) _F_Constructive
interference
occurs
when
peaks
of
one
wave
coincide
with
the
 troughs
of
another.
 3. 
 An
atom
as
a
principal
quantum
number
of
n
=
4.

Answer
the
following.
(6pts)

 
 
 a) What
are
all
of
the
possible
orbital
angular
momentum
numbers
(l)?
(2pts)
 
 
 
 


 l
=
3,2,1,0
 b) What
are
all
of
the
possible
magnetic
quantum
numbers
(ml)?
(1pt)
 
 
 
 
 ml

=
‐3,‐2,‐1,0,1,2,3
 
 c) Draw
representative
shapes
for
each
of
the
following
orbitals
on
the
coordinate
 axes
(3pts)
 s‐orbital
 p‐orbital
 d‐orbital
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 +
 ‐
 Quiz
2
(10/13/2008)
Sections
E04/E05
 4. 
 c) The
energy
required
to
eject
electrons
from
the
surface
of
a
metal
at
a
velocity
of
 _613_km/s
is
2.84x10‐22
KJ.

The
work
function
for
this
particular
metal
is
1.13x10‐ 19J.

(Show
Work)
(3pts)
 
 Units
conversion:

 
 
 
 ‐22
KJ
=
2.84x10‐19
J
 2.84x10 

 
 
 
 
 

 
 
 
 Etot
=
Ek
+
Eφ 
 

 

 
 
 
 
 
 
 








2.84x10‐19
J

=
Ek
+

1.13x10‐19J
 
 
 


Ek
=
1.71
*
10‐19
J
 
 
 
 
 
 
 
 
 
 
 
 
 
 EK
=
½mv2
 

1.71
*
10‐19
J
=
½(9.10939
*
10‐31)
v2
 
 
 V
=

21.71
∗
J9.10939
∗
10−31
 
 
 
 
 
 V=
613
*
103

or
613 
 
 
 
 d) 
Where
on
the
electromagnetic
spectrum
(as
in
to
which
type
of
light
does
this)
 does
this
radiation
correspond
to?
(Show
Work)
(3pts)
 
 
 
 
 c
=
νλ

 
 
 
 E=
hν
 
 
 
 
 
 
 λ 
 = 
 
ℎ E 
 
 
 
 
 
 
 
 
 

 λ
=
6.62608
x
10−34Js(2.99792
x

ms−12.84x10−19
J

 



=
700nm=
red
light/
visible
light
 5. T/F
(2pts
each)
 e) _T_
A
blackbody
object
does
not
absorb/emit
only
one
particular
wavelength.

 
 
 f) _T_The
Heisenberg
Uncertainty
Principle
shows
us
we
cannot
know
the
location
 and
the
momentum
of
a
particle.
 g) _T_The
probability
density
is
zero
at
a
node.
 
 
 
 
 h) _T_Constructive
interference
occurs
when
peaks
of
one
wave
coincide
with
the
 peaks
of
another.
 6. 
 An
atom
as
a
principal
quantum
number
of
n
=
5.

Answer
the
following.
(6pts)

 d) What
are
all
of
the
possible
orbital
angular
momentum
numbers
(l)?
(2pts)
 
 
 
 
 l
=

4,3,2,1,0
 
 
 e) What
are
all
of
the
possible
magnetic
quantum
numbers
(ml)?
(1pt)
 
 
 
 
 ml
=
‐4,‐3,‐2,‐1,0,1,2,3,4
 
 f) Draw
representative
shapes
for
each
of
the
following
orbitals
on
the
coordinate
 axes
(3pts)
 s‐orbital
 p‐orbital
 d‐orbital
 
 
 
 
 
 
 
 
 
 
 
 
 
 +
 ‐
 ...
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This note was uploaded on 12/07/2009 for the course CHEM CHEM 6A taught by Professor Czarkowski during the Fall '07 term at UCSD.

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