11.heating curve

11.heating curve - Question 11.33-11.40 in the back of the...

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Question 11.33-11.40 in the back of the chapter all deal with the total amount of energy absorbed (or given off) along a heating (or cooling) curve as first described on page 456. There is one problem like it on MC as well. I realize that I did not include a problem in recitation, so I am writing this to walk you through a problem, so you can have practice. We saw in class that the total amount of energy absorbed is from the following sequence: Heat solid -----> melt solid -----> heat liquid -----> boil liquid -----> heat gas When you melt the solid, you use the enthalpy of fusion, H fus , to calculate the amount of heat absorbed. This is a stoichiometric problem and H fus is a conversion factor. Ex. How much heat is absorbed when 5.30 g of ice is melted at 0.00 o C? H fus of water = 6.01 kJ/mol. Ans. 1.77 kJ Similarly when you boil the liquid, you use the enthalpy of vaporization, H vap , to calculate the amount of heat absorbed. H vap is another conversion factor.
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This note was uploaded on 12/09/2009 for the course CHEM 105 taught by Professor Macedone during the Spring '07 term at BYU.

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