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Unformatted text preview: MAE 101
Midterm Examination #1 October 26, 2009 Instructor: Professor Gupta
TA: Jason Citron; J aedal Jung DO ALL WORK ON THE EXAM
ATTTACH ADDITIONAL SHEETS AS NEEDED
WRITE YOUR NAME ON EVERY SHEET YOU USE NOTE: ALL EQUATIONS OF EQUILIBRIUM MUST HAVE
ASSOCIATED FREE BODY DIAGRAMS, WHICH MUST BE
DRAWN NEATLY Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9 TOTAL (100) NAME: ID: i
Problem 1 (10 points). Which of the following two truss designs (A or B) should a g designer choose? Please explain by discussing forces in one or two members at most. 5 Problem 2 (5 points). What is the direction of the internal force in the member AB in
the frame shown in Figure 2. That is, if you Were to cut this member, what angle, if any,
this internal force will makewith respect to the axis of the member? Explain your
answer. Hint: You do not have to solve for any member forces. ° Mo ‘Po'rce. cue)“ we (YMMpr End of ’H’le member i$ Pint/164 i
g Problem 4 (5 points). Two circular cylinders are compressed together through an axial
force F as shown. The crosssectional area of cylinder A is twice the crosssectional area
of cylinder B. Cylinder B rests on a smooth surface. Neglect the weights of both
cylinders. Determine (1) the magnitude and direction of the reaction imposed on cylinder
A by cylinder B, and (2) what is the magnitude and direction of the force imposed by the
cylinder B onto the smooth surface. Smooth Surface l. Problem 6 (5 points). Is the two dimensional body shown under the inﬂuence of foices
F1, F2 and F3 in equilibrium? Explain your answer. No points for just mentioning yes
or no. NO. ZMR #30. Problem 7 (25 points). Find ALL the reactions that the FIXED SUPPORT will impose
onto the beam at point A. Write them using the vector notation. Show the reactions on a
neatly sketched free body diagram. The load 2P is acting along the axis. Egg. gimaitbmwt (iiﬁweg) 2R: Ax= D APO » or “is”?
31m: Ar? :0 ‘9“ .._ 7
ER we“? '2 0 ‘LA: (PM *" CAPE W
M i6 witbtwm (‘if'lowuwdQ
: Mag ~= MA. ‘3.“ MBl = 0
3M3 : W,er e
.72: Me = Mi/Q'Jt M32; * O {Nil1er
M n A I l .3 k _
B i AB ’17:}; — at O b T— t'+(lc\r)\j“(i\f)k ﬁesma Wm, @zowwﬁé firm/airman ff/RL
Ni .= ‘* Wane. “0 (amid a) Past rm oar R OOH3. folk HMS? r 3123?“ Problem 9 (20 points). What is the maximum force F which can be placed 011 the
structure in the upward direction, as shown in the figure, assuming that the supports have
unlimited strength in tension and only 140 kN under compression. Which joint will fail
at the maximum load? 9e Eﬁudih‘r‘lqﬂm (ﬂue) '* git/thwmm (WWW?)
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This note was uploaded on 12/09/2009 for the course MAE 210306200 taught by Professor Chatterjee during the Fall '09 term at UCLA.
 Fall '09
 Chatterjee

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