Exam-1-key - NAME:_ KEY _ Page 1 (1) [15 points] Scientists...

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NAME:______ KEY _______ Page 1 (1) [15 points ] Scientists studying pond scum at ASU have found an organism with four sexes. Suppose the parents are P1= AAAa, P2 = AAaa, P3 = AAAA, and P4 = Aaaa. (a) What is the probability of getting an AAAA offspring? (3/4)*(1/2)*(1)*(1/4) = 3/32 = 0.09375 (b) What is the probability of getting an AAAa offspring? a from P1: (1/4)*(1/2)*(1)*(1/4) = 1/32 = 0.03125 a from P2: (3/4)*(1/2)*(1)*(1/4) = 3/32 = a from P3: (3/4)*(1/2)*0*(1/4) = 0 a from P4: (3/4)*(1/2)*(1)*(3/4) = 9/32 = 0.28125 total = 13/32 = 0.40625 (c) Given that the offspring is AAAa, what is the chance that Parent four (P4) contributed the a allele? (9/32)/(13/32) = 9/13 = 0.6923 (2) [10 points ] Consider a cross of AABBCcDD x AaBbCcDd. (a) What is the probability of an A-B-C-D- offspring? (Loci unlinked) 1*1*(3/4)*1 = 3/4 = 0. .75 (b) Given your answer (a), what is the probablity that the first five offspring are all A-B-C-D-? (3/4) 5 = 0.2373 (c) What is the probability that none of the first five offspring are A-B-C-D-? (1/4) 5 = 0.000977
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NAME:______ KEY _______ Page 2 (3) [15 points ] Two autosomal loci determine the dreaded sparky phenotype: the mustard locus (with alleles M = mustard, m = normal) and the rust locus (alleles R = rust, r = normal).
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Exam-1-key - NAME:_ KEY _ Page 1 (1) [15 points] Scientists...

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