Solution05

Solution05 - (1 The force acting on a window F = p 2 A(2 where A = area of the window Step-5 Known parameters z 1 = z 2 p 1 = p atm = 0 u 1 = 27.8

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Solution to Homework Assignment #5 Problem-1: Solution
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Problem-2: SOLUTION: Step-1: Find the force acting on a window facing the wind. Step-2: A plan view of the window is shown in Fig. 1. Window is a stagnation region where the wind speed is brought to zero. Fig. 1. Plan view of the window facing the storm Step-3: Assumption: The wind flow is steady, incompressible, and inviscid. The pressure p upstream in the wind is zero. Step-4: Equations The Bernoulli’s equation then allows us to calculate the pressure on the window:
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Unformatted text preview: (1) The force acting on a window F = p 2 A (2) where A = area of the window. Step-5: Known parameters z 1 = z 2 , p 1 = p atm = 0, u 1 = 27.8 m/s, u 2 = 0 m/s, A = 1m × 2m = 2 m 2 . Step-6: Calculations Substitution of the known values into Eq. (1) yields 2 2 2 1 2 N/m 464 2 (27.8) 1.2 2 = × = = V p ρ Substituting p 2 = 464 N/m 2 and A = 2 m 2 into Eq. (2) gives F = 464 × 2 = 928 N against window . 2 1 g V z p g V z p 2 2 2 2 2 2 2 1 1 1 + + = + + γ Problem-3: Solution Problem-4: Solution...
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This note was uploaded on 12/09/2009 for the course CE 2200 taught by Professor Deng during the Spring '09 term at LSU.

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Solution05 - (1 The force acting on a window F = p 2 A(2 where A = area of the window Step-5 Known parameters z 1 = z 2 p 1 = p atm = 0 u 1 = 27.8

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