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Unformatted text preview: 1115 The wooden membersA and B are to be joined by plywood splice plates which
will be ﬁilly glued on the surfaces in contact, As part of the design of the joint and
knowing that the clearance between the ends of the members is to be 8 mm, determine the smallest allowable length L if the average shearing stress in the glue is not to exceed
800 kPa. PROBLEM 1.15 SOLUTION There are ¥ow Sepawde areas 6’? algae. EaOA
Meat ms+ +mV.sm+ m1); 0+ ‘Hca. 2m; «panel. The,” gain! F f .1. [RX ‘03 N Sherwina 5+mss in {glue 4: = goo x103 Pa. Ft F x/3 3
1“? ~' A ?='é:%z%=/5*IO m 2. ll Le‘l‘ J = Jamal!" 6F 3‘qu area. anal w: writh = loo Mm = O. w. —3 : low) .2 ﬂ :: 1’2. = “150.310 = [6'0 W[Di3w. = LSD mm
22 4 3%,) = (2309334 3 .. 308 MM ‘ 1.16 Determine the diameter of the largest circular hole which can be punched into
PROBLEM 1‘16 a sheet of polystyrene 6mm thick, knowing that the force exerted by the punch is 45
kN and that a 55MPa average shearing stress is required to cause the material to fail. SOLUTION A '5 'lT Cl t 43:» cyapinolm‘cup Fauyuw .1: a)"; 9.4m;
‘» em" 'nta S‘l'NSS ’K = IP 3‘ A = '17;
Eat/tufan A \S g “:7  ' — Mﬁa "5 I
Savanna ‘PDV‘ A  :ﬁ,%—,E  “(O'Doé)($_xlobj 43.4)(10 In
a: 43.4w 4 PROBLEM 1.19 1.19 The axial force in the column supporting the timber beam shown is P = 75 kN. Determine the smallest allowable length L of the bearing plate if the bearing stress in
the timber is not to exceed 3.0 MPa. ‘ SOLUTION Saivmca ‘Foxﬁ L. ' L 55w ~L3~oxfOEX0J¥O> I7$.6><Io'3 m
L: 178.6 mm ‘ ll 1.20 An axial load P is supported by a short W250 >< . 67 column of crosssectional
area A = 8580 mm2 and is distributed to a concrete foundation by a square plate as
shown. Knowing that the average normal stress in the column must not exceed 150
MPa and that the bearing stress on the concrete foundation must not exceed 12.5 MPa,
determine the side a of the plate which will provide the most economical and safe
designs 9 PROBLEM 1.20 SOLUTION
Awea a? ado“: A = 3530mm1= 3520 x10" w”
Normal .S‘i'lﬂess in Column? (5' : I50 W0é Pa.
5': 7? .1 p: A 5‘: (gsaoscgd‘XISD x10“) : 1.227 x 10‘ N Beaming Pia/+3 I 61,: 2?; Mai A5: 0.2 1%» saloqu P/m‘i‘e. _ z _ _E___ 1.227wo" _ '3
AL  a _ 61 _ 125*!“ _ 3:2leo m w 325wm “‘3 PROBLEM 1.25 1.9 Two horizontal 5kip forces are applied to pin B of the assembly shown. Knowing
that a pin of 0.8in. diameter is used at each connection, determine the maximum value
of the average normal stress (a) in link AB, (b) in link BC . 0'5 in' 1.25 For the assembly and loading of Prob, 1.9, determine (a) the average shearing
stress in the pin at A, (b) the average bearing stress at A in member AB. SOLUTION
skips use JONf B as ‘pree body.
Skips *
0.5m. to [UPS Fa:
Force +m'an 1ft: FAB = k‘FS (a) Sheari'nﬁ s+ress in PM of!" A 2’ = ').r~'lw2:w~a [\f: l‘Edz : 1L;L(O°8)z : 05026 1": ,1: t 7. 3205’ (21(5.;$’026) = 7‘ 22 (b) Beabin?) sfrcss ail A in member A8 A1) = to? = (053018) = 0.4 in‘  FAB _ 7.3205 _  .
61, , Ab _ —————~o_4  13.30 12.30145, «4 ...
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 Fall '09
 MOORTHY

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