HW2 - 1115 The wooden membersA and B are to be joined by...

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Unformatted text preview: 1115 The wooden membersA and B are to be joined by plywood splice plates which will be fiilly glued on the surfaces in contact, As part of the design of the joint and knowing that the clearance between the ends of the members is to be 8 mm, determine the smallest allowable length L if the average shearing stress in the glue is not to exceed 800 kPa. PROBLEM 1.15 SOLUTION There are ¥ow Sepawde areas 6’? algae. Ea-OA Meat ms+ +mV.sm+ m1); 0+ ‘Hca. 2m; «panel. The,” gain! F f .1. [RX ‘03 N Sherwin-a 5+mss in {glue 4: = goo x103 Pa. Ft F x/3 -3 1“? ~' A ?='é:%z%=/5*IO m 2. ll Le‘l‘ J = Jamal!" 6F 3‘qu area. anal w: writ-h = loo Mm = O.| w. —3 -: low) .2 fl :: 1’2. = “150.310 = [6'0 W[Di-3w. = LSD mm 22 4- 3%,) = (2309334- 3 .-. 308 MM ‘ 1.16 Determine the diameter of the largest circular hole which can be punched into PROBLEM 1‘16 a sheet of polystyrene 6-mm thick, knowing that the force exerted by the punch is 45 kN and that a 55-MPa average shearing stress is required to cause the material to fail. SOLUTION A '5 'lT Cl t 43:» cyapinolm‘cup Fauyuw .1: a)"; 9.4m; ‘» em" 'nta S‘l'NSS ’K = IP- 3‘ A = '17; Eat/tufan A \S g “:7 - ' — -Mfia "5 I Savanna ‘PDV‘ A - :fi,%—,E - “(O'Doé)($_xlobj 43.4)(10 In a: 43.4w 4 PROBLEM 1.19 1.19 The axial force in the column supporting the timber beam shown is P = 75 kN. Determine the smallest allowable length L of the bearing plate if the bearing stress in the timber is not to exceed 3.0 MPa. ‘ SOLUTION Saivmca ‘Foxfi L. ' L 55w ~L3~oxfOEX0J¥O> I7$.6><Io'3 m L: 178.6 mm ‘ ll 1.20 An axial load P is supported by a short W250 >< . 67 column of cross-sectional area A = 8580 mm2 and is distributed to a concrete foundation by a square plate as shown. Knowing that the average normal stress in the column must not exceed 150 MPa and that the bearing stress on the concrete foundation must not exceed 12.5 MPa, determine the side a of the plate which will provide the most economical and safe designs 9 PROBLEM 1.20 SOLUTION Awea a? ado“: A = 3530mm1= 3520 x10" w” Normal .S‘i'lfless in Column? (5' : I50 W0é Pa. 5': 7? .1 p: A 5‘: (gsaoscgd‘XISD x10“) : 1.227 x 10‘ N Beaming Pia/+3 I 61,: 2?; Mai A5: 0.2 1%» saloqu P/m‘i‘e. _ z _ _E___ 1.227wo" _ '3 AL - a _ 61 _ 125*!“ _ 3:2leo m w 325wm “‘3 PROBLEM 1.25 1.9 Two horizontal 5-kip forces are applied to pin B of the assembly shown. Knowing that a pin of 0.8-in. diameter is used at each connection, determine the maximum value of the average normal stress (a) in link AB, (b) in link BC . 0'5 in' 1.25 For the assembly and loading of Prob, 1.9, determine (a) the average shearing stress in the pin at A, (b) the average bearing stress at A in member AB. SOLUTION skips use JON-f B as ‘pree body. Skips * 0.5m. to [UPS Fa: Force +m'an 1ft: FAB = k‘FS (a) Sheari'nfi s+ress in PM of!" A 2’ = ').r~'lw2:w~a [\f: l‘Edz : 1L;L(O°8)z : 0-5026 1": ,1: t 7. 3205’ (21(5.;$’026) = 7‘ 22 (b) Bea-bin?) sfrcss ail A in member A8 A1) = to? = (0-53018) = 0.4 in‘ - FAB _ 7.3205 _ - . 61, , Ab _ ——-———~o_4 - 13.30 12.30145, «4 ...
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HW2 - 1115 The wooden membersA and B are to be joined by...

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