This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: pROBLEM 9_1 9.] through 9.4 For the loading shown, determine (a) the equation of the elastic curve for the cantilever beam AB, (b) the deﬂection at the free end, (c) the slope at the free
end. SOLUTION (a) Epas+fc Cu r ve 9.1 through 9.4 For the loading shown, determine (a) the equation of the elastic curve
PROBLEM 9.4 for the cantilever beam AB, (b) the deﬂection at the free end, (c) the slope at the free
end. SOLUTION IZOL OI—O+O—O+O +0: 1. .
(a) EmuHe Curve : —ﬂe._ (ELLz’x, — ﬁLx" + J—X“) '20 (la) y@x=L PROBLEM 9,9 9.9 and 9.10 For the beam and loading shown, (a) express the magnitude and location
of the maximum deﬂection in terms of w, L, E, and I . (b) Calculate the value of the
maximum deﬂection, assuming that beam AB is a W!!! X 50 rolled shape and that w" =
4.5 kips/ﬁ, L = 18 ﬂ, and E = 29 X 10‘ psi. “It, SOLUTION Ustna en‘krz beam as Q 'Free lamb; 92MB = o 43.1. +(JaW9Ll(§)=o
RA t'éw‘J‘ Usénﬂ AI «.5 4.43m: Lady 92MJ = o 1
—é—w.Lx+(§1"fl)(—§)+ M = o [w=o,]=o] oro—0+o +C.‘z C‘=o wL‘
fxrlJJHD] o = é‘zWoL',,L;W0L’ + CL 4 o C 7 — gag... l
.5
Epcesl'ic curve 3/ = Eff {iLXS ;21; “E— 37:_’ Ex}
al N " 7
2:? emf55f “.37an
To Ixu‘i'u‘on 0F laminarn Jajeg‘f‘ion 53‘," Si = O :_ q_ q
o x1"= BOL 17001. HZOL '1ij  30!.”th + 7H ll "" ‘50
x; _(l JEM‘ = 01:97 Lz xhr 0.5:93 L .
3”: ﬁgsslaL(o_51q3L)3_uLa W) 530 L3(0.5l‘?3 1.)}
ll
=  0.00652 or 0.00652 # l "" w.= 45 ups/H = 5%? = 375 IL/i‘nd L= 18H  21cm.
1 = 800 M‘ 4?... wlsxs‘o _ (0.00652 3(375) :UGY' _ .
3”“ “7" "' ...
View
Full
Document
This note was uploaded on 12/09/2009 for the course CE 3400 taught by Professor Moorthy during the Fall '09 term at LSU.
 Fall '09
 MOORTHY

Click to edit the document details