HW1Sol

# HW1Sol - (Eq.2 where L is the length of the sample(along...

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EECE 321: Electronics-I (Spring 2007, University of New Mexico) Homework-I (Due Date: Monday, Jan 29 th , In class) 5 Points for each problem

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4. Show that the equation J = σ E, where J is the current density, σ is the conductivity and E is the applied electric field (constant) is just a microscopic restatement of the Ohm’s law (V=IR). Solution: Start from Ohm’s law V=IR (Eq.1) We know that for a constant electric field,E, the potential difference, V is given by V = E.L
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Unformatted text preview: (Eq.2) where L is the length of the sample (along which the electric field is applied). We also know that the current density, J is related to the total current, I, by, J = I/A (Eq.3) where A is the area of the sample (through which the current flows). Finally, we know that the resistance, R is given by A L A L R σ ρ = = (Eq.4) where the resistivity, ρ , is the reciprocal of the conductivity, σ . Substitute Eq. 2,3,4 in Eq. 1 (Ohms law) to get J = σ E...
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HW1Sol - (Eq.2 where L is the length of the sample(along...

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