2002 key - Name CHEMISTRY 3311 Fall 2002 Professor Walba First Hour Exam September 26 scores 1 2 3 4 5 20 20 20 20 20 100 Key This is a closed-book

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Unformatted text preview: Name: CHEMISTRY 3311, Fall 2002 Professor Walba First Hour Exam, September 26 scores: 1) 2) 3) 4) 5) 20 20 20 20 20 100 Key This is a closed-book exam. The use of notes, models, calculators, and other paraphernalia will not be allowed during the exam. Please put all your answers on the test. Use the backs of the pages for scratch. PLEASE read the questions carefully! 1A 1 H Partial Periodic Table 2A 3 4 Li Be 11 12 Na Mg 3A 4A 5A 6A 7A 5 6 7 8 9 10 B C N O F Ne 13 14 15 Al Si P 16 S 17 18 Cl Ar 35 Br 53 I 8A 2 He -1- Name: Key 1 (20 pts) a) Describe the relationship between each of the following pairs of structures using one of the following pairwise descriptors: homomers; constitutional isomers; stereoisomers. F F F F F F homomers stereoisomers F F F F F Br Br F constitutional isomers homomers b) Each of the following pairs of compounds can in principle act as a Bronsted acid (i.e. can donate a proton to a base). For each pair, circle the stronger acid. NH3 CH4 NH2 OH ii i NH3 OH2 HBr HF H 3C CH 3 F F OH OH c) In ONE WORD, give a reason for your answer in part 1.b.iii. Electronegativity -2- Name: Key 2) (20 pts) a) Draw a wedges and dashes structure for the conformation of 1-bromo-1-chloro-3,3-dimethylbutane shown in the Newman projection below. This is a chlorine H H Br Cl H Cl Br Dihedral angle for Cl-C(1)-C(2)-C(3) = 60° b) Sterically, a bromine atom is bigger than a chlorine (the van der Waals diameter of bromine is about 2.3 Å, and the diameter of chlorine is only 2.0 Å). Complete the conformational energy diagram below for rotation about the C(1)-C(2) bond (please rotate the front carbon (C1)). Define the 60° dihedral angle as the conformation shown above. Be sure to carefully indicate the relative energy of each well and barrier in your energy diagram, and complete the Newman projections for the 180° and 300° conformations. -3- Name: Key 3) (20 pts) a) For each pair of isomers in the boxes below, circle the more stable isomer. 1 2 3 4 b) Draw the two flip-chair conformations of compound 4 below. c) Circle the more stable conformation. d) Indicate in writing with a numbers (not on the structures) how many gauche butane (1,3-diaxial Methyl-H) interactions, and how many syn-pentane (1,3-diaxial Methyl-Methyl) interactions each conformation has. That is, for each flip chair form of compound 4, you should write “x gauche butane interactions” and “y synpentane interactions” where x and y are the correct numbers. e) DON’T FORGET TO DO PARTS 3C AND 3D!!! 2 gauche butane interactions 1 syn-pentane interaction 2 gauche butane interactions -4- Name: Key 4) (20 pts) Give the structure of the single major organic product formed from each of the following reactions. Each structure should be a valid valence bond structure, showing loan pairs and correct formal charges on all the atoms (of course, if the formal charge on an atom is 0, then you don’t show it). HBr a) N H H N H (C4H1 0N) HBr b) OH C5H9Br Br c) Br2, hn Br The following reaction gives two major products! Draw structures for these two products. Cl d) OH HCl Cl TWO maj or products wi th MF = C8 H1 5Cl Propose reagents for accomplishing the following transformation. e) SOCl 2, pyr OH -5Cl Name: Key 5) (20 pts) Propose arrow-pushing mechanisms for each of the following transformations. Be sure to show valid valence bond structures (with loan pairs and formal charges) for each intermediate in your mechanisms, but please do not show transition states. HBr a) OH Br OH + Br Br OH H + H O H H Br HBr b) OH Br + H O H Br H +H O H Br O H -6- Name: 5 –continued- Key c) For the two reactions indicated below, complete the energy diagrams, carefully showing the relative energy of each intermediate and transition state. Please assume that the energy scale is the same in each diagram, in order to indicate the relative energies of the transitions states for the two different reactions. Indicate a valid valence bond structure for each intermediate (do not show the actual structures of the transitions states). E OH H Br Br + H2O Rea cti on Coordi nate OH Br H2O + HBr + Br OH H E Br + H2O Rea cti on Coordi nate OH + HBr -7- Br + H2O Name: Key 5 –continuedd) For four points, propose a structure for the product of the following reaction. HBr HO O C4 H9OBr Br -8- ...
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This note was uploaded on 12/10/2009 for the course CHEM 3311 at Colorado.

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