Lecture 10.23.09

# Lecture 10.23.09 - Ψ 2 =(constant(e-2r/a where a = 53 pm...

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Friday, October 23 CHEM 1251, Fall 2009 1 Don’t forget to buy a cupcake from the Noon to 1:30 between Ekeley and Cristol. Cost is a penny a proton, up to 50 cents. 2 The probability ( Ψ 2 ) that an electron can be found at a particular distance from the nucleus (r), is given by this equation: Ψ 2 = (constant)(e -2r/a 0 ) where a 0 = 53 pm. Interpret the equation to determine which statement best describes the probability of finding the electron infinitely far from the nucleus. A. High probability (constant * big number) B. Low probability (constant * small number) C. Negative probability (constant * negative number) D. Nearly zero probability (constant * nearly zero) CQ #1 3 The probability ( Ψ 2 ) that an electron can be found at a particular distance from the nucleus (r), is given by this equation:

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Unformatted text preview: Ψ 2 = (constant)(e-2r/a ) where a = 53 pm. According to this, where is the maximum probability of finding the electron? A. Just outside the nucleus B. In the middle of the nucleus C. About 53 pm from the nucleus D. Not really sure how to interpret the equation CQ #2 4 Figure 7.15 Ψ 2 = (constant)(e-2r/a ) 5 Figure 7.16 1s 2s 3s 6 Figure 7.17 2p orbitals Friday, October 23 CHEM 1251, Fall 2009 7 Figure 7.18 3d orbitals 8 Which orbital has the highest probability of finding the electron close to the nucleus? A. 3d B. 4p C. 5s CQ #3 9 Additional Information Answers to today ’ s clicker questions ( CQs ) CQ #1: D CQ #2: B CQ #3: C Preparing for future learning Read Chapter 7, Sections 7.3 and 7.4 Read Chapter 8, Sections 8.1 - 8.3...
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## This note was uploaded on 12/10/2009 for the course CHEM 1111 at Colorado.

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Lecture 10.23.09 - Ψ 2 =(constant(e-2r/a where a = 53 pm...

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