hw3 - patel (kp9583) HW3 Mackie (20211) 1 This print-out...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: patel (kp9583) HW3 Mackie (20211) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. DEADLINE IS CENTRAL TIME 001 (part 1 of 2) 10.0 points Instructions for finding a buried treasure in- clude the following: Go 174 . 6 paces at 295 , turn to 114 and walk 103 paces, then travel 308 paces at 93 . Find the magnitude of the resultant dis- placement from the starting point. Correct answer: 243 . 942 paces. Explanation: Let east be 0 . Given : r 1 = 174 . 6 paces 1 = 295 r 2 = 103 paces 2 = 114 r 3 = 308 paces 3 = 93 . The horizontal component of the resultant is R x = R 1 cos 1 + R 2 cos 2 + R 3 cos 3 = (174 . 6 paces) cos295 + (103 paces) cos 114 + (308 paces) cos 93 = 15 . 7759 paces and the vertical component is R y = R 1 sin 1 + R 2 sin 2 + R 3 sin 3 = (174 . 6 paces) sin295 + (103 paces) sin 114 + (308 paces) sin 93 = 243 . 432 paces R 2 = R x 2 + R y 2 = 15 . 7759 paces 2 + 243 . 432 paces 2 = 59507 . 9 paces 2 , so | R | = radicalbig 59507 . 9 paces 2 = 243 . 942 paces 002 (part 2 of 2) 10.0 points What is the direction of the resultant displace- ment? Use counterclockwise from due East as the positive angular direction, between the limits of- 180 and +180 . Correct answer: 86 . 2921 . Explanation: tan = R y R x , so the direction of R is = arctan parenleftbigg R y R x parenrightbigg = arctan parenleftbigg 243 . 432 paces 15 . 7759 paces parenrightbigg = 86 . 2921 003 (part 1 of 2) 10.0 points A particle travels horizontally between two parallel walls separated by 18 . 4 m. It moves toward the opposing wall at a constant rate of 5 . 5 m / s. Also, it has an acceleration in the direction parallel to the walls of 1 . 3 m / s 2 . 18 . 4 m 1 . 3m / s 2 5 . 5 m / s What will be its speed when it hits the opposing wall? Correct answer: 7 . 01175 m / s. patel (kp9583) HW3 Mackie (20211) 2 Explanation: Let : d = 18 . 4 m , v x = 5 . 5 m / s , a = 1 . 3 m / s 2 , Basic Concepts Kinematics equations v = v o + g t s = s o + v o t + 1 2 g t 2 d a 4 . 34909m / s 5 . 5 m...
View Full Document

This note was uploaded on 12/10/2009 for the course PHYSICS 2021 taught by Professor Mihalisin during the Fall '09 term at Temple.

Page1 / 6

hw3 - patel (kp9583) HW3 Mackie (20211) 1 This print-out...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online