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# hw3 - patel(kp9583 HW3 Mackie(20211 This print-out should...

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patel (kp9583) – HW3 – Mackie – (20211) 1 This print-out should have 13 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. DEADLINE IS CENTRAL TIME 001 (part 1 of 2) 10.0 points Instructions for finding a buried treasure in- clude the following: Go 174 . 6 paces at 295 , turn to 114 and walk 103 paces, then travel 308 paces at 93 . Find the magnitude of the resultant dis- placement from the starting point. Correct answer: 243 . 942 paces. Explanation: Let east be 0 . Given : r 1 = 174 . 6 paces θ 1 = 295 r 2 = 103 paces θ 2 = 114 r 3 = 308 paces θ 3 = 93 . The horizontal component of the resultant is R x = R 1 cos θ 1 + R 2 cos θ 2 + R 3 cos θ 3 = (174 . 6 paces) cos 295 + (103 paces) cos 114 + (308 paces) cos 93 = 15 . 7759 paces and the vertical component is R y = R 1 sin θ 1 + R 2 sin θ 2 + R 3 sin θ 3 = (174 . 6 paces) sin 295 + (103 paces) sin 114 + (308 paces) sin 93 = 243 . 432 paces R 2 = R x 2 + R y 2 = 15 . 7759 paces 2 + 243 . 432 paces 2 = 59507 . 9 paces 2 , so | R | = radicalbig 59507 . 9 paces 2 = 243 . 942 paces 002 (part 2 of 2) 10.0 points What is the direction of the resultant displace- ment? Use counterclockwise from due East as the positive angular direction, between the limits of - 180 and +180 . Correct answer: 86 . 2921 . Explanation: tan θ = R y R x , so the direction of R is θ = arctan parenleftbigg R y R x parenrightbigg = arctan parenleftbigg 243 . 432 paces 15 . 7759 paces parenrightbigg = 86 . 2921 003 (part 1 of 2) 10.0 points A particle travels horizontally between two parallel walls separated by 18 . 4 m. It moves toward the opposing wall at a constant rate of 5 . 5 m / s. Also, it has an acceleration in the direction parallel to the walls of 1 . 3 m / s 2 . 18 . 4 m 1 . 3 m / s 2 5 . 5 m / s What will be its speed when it hits the opposing wall? Correct answer: 7 . 01175 m / s.

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patel (kp9583) – HW3 – Mackie – (20211) 2 Explanation: Let : d = 18 . 4 m , v x = 5 . 5 m / s , a = 1 . 3 m / s 2 , Basic Concepts Kinematics equations v = v o + g t s = s o + v o t + 1 2 g t 2 d a 4 .
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hw3 - patel(kp9583 HW3 Mackie(20211 This print-out should...

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