cw15 - · m . 002 10.0 points A one-piece cylinder has a...

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patel (kp9583) – CW15 – Mackie – (20211) 1 This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points A circular-shaped object oF mass 10 kg has an inner radius oF 5 cm and an outer radius oF 28 cm. Three Forces (acting perpendicular to the axis oF rotation) oF magnitudes 11 N, 23 N, and 13 N act on the object, as shown. The Force oF magnitude 23 N acts 32 below the horizontal. 11 N 13 N 23 N 32 ω ±ind the magnitude oF the net torque on the wheel about the axle through the center oF the object. Correct answer: 0 . 0557 N · m. Explanation: Let : a = 5 cm = 0 . 05 m , b = 28 cm = 0 . 28 m , F 1 = 11 N , F 2 = 23 N , F 3 = 13 N , and θ = 32 . F 1 F 3 F 2 θ ω The total torque is τ = a F 2 - b F 1 - b F 3 = (0 . 05 m) (23 N) - (0 . 28 m) (11 N + 13 N) = - 0 . 0557 N · m , with a magnitude oF 0 . 0557 N
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Unformatted text preview: · m . 002 10.0 points A one-piece cylinder has a core section pro-truding From the larger drum and is Free to ro-tate around its central axis. A rope wrapped around the drum oF radius 1 . 16 m exerts a Force oF 4 . 5 N to the right on the cylinder. A rope wrapped around the core oF radius . 58 m exerts a Force oF 6 . 92 N downward on the cylinder. 4 . 5 N 6 . 92 N What is the magnitude oF the net torque acting on the cylinder about the rotation axis? Correct answer: 1 . 2064 N · m. Explanation: Let : F 1 = 4 . 5 N , R 1 = 1 . 16 m , F 2 = 6 . 92 N , and R 2 = 0 . 58 m . τ net = τ ccw-τ cw = F 1 R 1-F 2 R 2 = (4 . 5 N)(1 . 16 m)-(6 . 92 N)(0 . 58 m) = 1 . 2064 N · m , which has a magnitude oF 1 . 2064 N · m ....
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This note was uploaded on 12/10/2009 for the course PHYSICS 2021 taught by Professor Mihalisin during the Fall '09 term at Temple.

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