cw9 - patel (kp9583) CW9 Mackie (20211) 1 This print-out...

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Unformatted text preview: patel (kp9583) CW9 Mackie (20211) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points An Olympic skier moving at 30 m / s down a 19 slope encounters a region of wet snow of coefficient of kinetic friction = 0 . 59. The acceleration of gravity is 9 . 8 m / s 2 . How far down the slope does she travel before coming to a halt? Correct answer: 197 . 679 m. Explanation: Align the x axis along the incline, and let down the incline be positive. The normal force is N = m g cos . Hence the frictional force is f = N = m g cos Applying Newtons second law to the skier along the incline yields summationdisplay F = m g sin - m g cos = m a , or solving for a , a = g [sin - cos ] = (9 . 8 m / s 2 ) [sin19 - (0 . 59) cos19 ] =- 2 . 27642 m / s 2 ....
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This note was uploaded on 12/10/2009 for the course PHYSICS 2021 taught by Professor Mihalisin during the Fall '09 term at Temple.

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cw9 - patel (kp9583) CW9 Mackie (20211) 1 This print-out...

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