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# cw8 - patel(kp9583 CW8 Mackie(20211 This print-out should...

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patel (kp9583) – CW8 – Mackie – (20211) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. DEADLINE IS CENTRAL TIME 001 (part 1 of 2) 10.0 points A light, inextensible cord passes over a light, frictionless pulley with a radius of 15 cm. It has a(n) 15 kg mass on the left and a(n) 5 kg mass on the right, both hanging freely. Initially their center of masses are a vertical distance 3 . 1 m apart. The acceleration of gravity is 9 . 8 m / s 2 . 3 . 1 m 15 cm ω 15 kg 5 kg At what rate are the two masses accelerat- ing when they pass each other? Correct answer: 4 . 9 m / s 2 . Explanation: Let : R = 15 cm , m 1 = 5 kg , m 2 = 15 kg , h = 3 . 1 m , and v = ω R . Consider the free body diagrams 15 kg 5 kg T T m 2 g m 1 g a a Since the larger mass will move down and the smaller mass up, we can take motion downward as positive for m 2 and motion up- ward as positive for m 1 . Apply Newton’s second law to m 1 and m 2 respectively and then combine the results: For mass 1: summationdisplay F 1 : T - m 1 g = m 1 a (1) For mass 2: summationdisplay F 2 : m 2 g - T = m 2 a (2) We can add Eqs. (1) and (2) above and obtain: m 2 g - m 1 g = m 1 a + m 2 a a = m 2 - m 1 m 1 + m 2 g = 15 kg - 5 kg 15 kg + 5 kg (9 . 8 m / s 2 ) = 4 . 9 m / s 2 .

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cw8 - patel(kp9583 CW8 Mackie(20211 This print-out should...

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