Unformatted text preview: the mass oF the lighter blocks is 9 kg and the magnitude oF the Force oF the connecting string on the smaller block is 27 N. Assume: g = 9 . 8 m / s 2 and the horizontal surFace on which the objects slide is Friction-less. 9 kg 18 kg 27 N F Determine the Force F . Correct answer: 81 N. Explanation: Let : M = 9 kg , 2 M = 18 kg , and T = 27 N . M 2 M T T F ±or each body, F net = m a . ±or the leFtmost block, the tension acts to the right, so M a = T a = T M ±or the rightmost block, the Force acts to the right and the tension to the leFt, so 2 M a = F-T F = T + 2 M a = T + 2 M T M = 3 T = 3 (27 N) = 81 N ....
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This note was uploaded on 12/10/2009 for the course PHYSICS 2021 taught by Professor Mihalisin during the Fall '09 term at Temple.
- Fall '09