cw6 - patel (kp9583) CW6 Mackie (20211) 1 This print-out...

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Unformatted text preview: patel (kp9583) CW6 Mackie (20211) 1 This print-out should have 5 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. DEADLINE IS CENTRAL TIME 001 10.0 points Assume: A 78 g basketball is launched at an angle of 53 . 5 and a distance of 13 . 1 m from the basketball goal. The ball is released at the same height (ten feet) as the basketball goals height. A basketball player tries to make a long jump-shot as described above. The acceleration of gravity is 9 . 8 m / s 2 . What speed must the player give the ball? Correct answer: 11 . 5865 m / s. Explanation: Basic concepts: Horizontally, v oh = v cos v h = v oh d = v oh t Vertically, v ov = v sin v v = v ov- g t h = v ov t- 1 2 g t 2 . Solution: At the maximum range of the ball, v fv =- v ov , so,- v ov = v ov- g t- 2 v ov =- g t t = 2 v ov g . The maximum distance covered is d = v oh t = 2 v oh v ov g d = 2 v cos v sin g d = v 2 (2 sin cos )...
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cw6 - patel (kp9583) CW6 Mackie (20211) 1 This print-out...

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