cw5 - Correct answer: 39 . 1008 m. Explanation: Basic...

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patel (kp9583) – CW5 – Mackie – (20211) 1 This print-out should have 3 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. DEADLINE IS CENTRAL TIME 001 10.0 points An autographed baseball rolls o± oF a 1.2 m high desk and strikes the ²oor 0.41 m away From the desk. The acceleration oF gravity is 9 . 81 m / s 2 . How Fast was it rolling on the desk beFore it Fell o±? Correct answer: 0 . 82892 m / s. Explanation: v x 1 . 2 m 0 . 41 m Note: ³igure not drawn to scale Basic Concepts: Horizontally, Δ x = v i,x Δ t + 1 2 a x t ) 2 = v x Δ t since a x = 0 m/s 2 . Vertically, Δ y = v i,y Δ t - 1 2 g t ) 2 = - 1 2 g t ) 2 since v i,y = 0 m/s. Given: Δ y = - 1 . 2 m Δ x = 0 . 41 m g = 9 . 81 m / s 2 Solution: Equating the times, Δ t = r 2 Δ y - g = Δ x v x v x = R - g y Δ x = r - 9 . 81 m / s 2 2( - 1 . 2 m) (0 . 41 m) = 0 . 82892 m / s . 002 (part 1 oF 2) 10.0 points An arrow is shot at 37 angle with the hori- zontal. It has a velocity oF 46 m / s. The acceleration oF gravity is 9 . 8 m / s 2 . How high will the arrow go?
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Unformatted text preview: Correct answer: 39 . 1008 m. Explanation: Basic Concepts Horizontally, v oh = v cos v h = v oh d = v oh t and vertically, v ov = v sin v v = v ov-gt h = v ov t-1 2 gt 2 maximum height, so 0 = v ov-gt so that t = v ov g Thus the maximum height is h max = v ov v ov g-1 2 g p v ov g P 2 = 1 2 v 2 ov g Dimensional analysis For h max : m s m s 2 = m s s 2 m = s 003 (part 2 oF 2) 10.0 points What horizontal distance will it travel? Correct answer: 207 . 554 m. patel (kp9583) CW5 Mackie (20211) 2 Explanation: The horizontal velocity is constant, and the maximum range is attained in a time of 2 t , so d = v oh 2 t = v oh 2 v ov g = 2 v oh v ov g Dimensional analysis for d : m s m s m s 2 = m 2 s 2 s 2 m = m...
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cw5 - Correct answer: 39 . 1008 m. Explanation: Basic...

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