Solutions_Quiz5_To_Quiz8

Solutions_Quiz5_To_Quiz8 - Node 2 choose the same value is...

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TELCOM 2310 – Fall 2009 Solutions for Quiz 5, Quiz 6, Quiz 7, and Quiz 8 Quiz #5 1 0 0 0 0 0 10 10 10 10 0 10 11 0 10 11 0 10 11 1 00 10 1 0 0 1 1 0 10 11 0 01 100 1 0 10 11 1 00 11 1 0 0 1 1 01 010 1 0 10 11 0 01 010 100 0 10 11 0 00 01 00 G D R Quiz #6 Assume that c1 <= c2 <= c3 <= 10. A collision would occur if one of the following events happens: (i) Node 1 and Node 2 choose the same K, OR (ii) Node 1 and Node 3 choose the same K, OR (iii) Node 2 and Node 3 choose the same K. (The event where the three of them choose the same K is included in these cases). There are 2 c1 x 2 c2 possible pairs of values that Node 1 and Node 2 may choose. Out of these, only 2 c1 pairs have identical values (since c1 <= c2). So, the probability that Node 1 and
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Unformatted text preview: Node 2 choose the same value is: P 1,2 = 2 c1 / (2 c1 x 2 c2 ) = 1/2 c2 Similarly, P 1,3 = 2 c1 / (2 c1 x 2 c3 ) = 1/2 c3 And P 2,3 = 2 c2 / (2 c2 x 2 c3 ) = 1/2 c3 So, the probability that a collision occurs next is: P 1,2 + P 1,3 + P 2,3 = 1/2 c2 + 1/2 c3 + 1/2 c3 = 1/2 c2 + 2/2 c3 Quiz #7 Question: How many different multicast IP addresses at most can share the same MAC address? Answer: 2 5 = 32 . Because of the five bits in pink in slide 64 (of Chapter 5) about Mapping of Multicast IP Addresses to IEEE 802 Multicast MAC Addresses Quiz #8 Plain text = 010 110 001 111 Ciphertext = 101 000 111 001...
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Solutions_Quiz5_To_Quiz8 - Node 2 choose the same value is...

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