{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# HW2 - momin(rrm497 Homework 2 Sutclie(53120 This print-out...

This preview shows pages 1–3. Sign up to view the full content.

momin (rrm497) – Homework 2 – Sutcliffe – (53120) 1 This print-out should have 18 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. This assignment is due at 11pm on the date indicated in the assignment menu on Quest. 001 10.0 points Ψ 2 ( x,y,z ) is related to 1. the Laplacian transform of the Bohr equa- tion. 2. the probability of finding an electron at the point ( x,y,z ) in space with the origin (0) at the nucleus. correct 3. Bohr magnetons. 4. the probability of a p orbital becoming an s orbital. 5. the nocturnal emissions of mercury lamps. Explanation: Ψ 2 gives the probability of finding an elec- tron in a particular infinitesimally small vol- ume of space in an atom. 002 10.0 points In a one-dimensional particle in a box, for Ψ 4 , how many nodes are predicted? 1. 3 correct 2. 1 3. 4 4. 0 5. 2 Explanation: 003 10.0 points What is the subshell notation and the number of orbitals that can have the quantum num- bers n = 1 , ℓ = 0? 1. 1 p ; 5 2. 1 p ; 1 3. 1 s ; 1 correct 4. None of these 5. 1 s ; 2 6. 1 p ; 2 Explanation: The notation is n where n = 1 , 2 , 3 , 4 , 5 , · · · = 0 , 1 , 2 , · · · , ( n - 1) represented by a letter: value 0 1 2 3 4 5 letter s p d f g h m = - ℓ, - ( - 1) , - ( - 2) , · · · , 0 , · · · +( - 2) , +( - 1) , + and m s = ± 1 2 . To find the number of orbitals that can have the stated values of n and (and any allowed values of m and m s ), use to find the number of different values of m . To find the maximum number of electrons that can have the stated values of n and (and any allowed value of m and m s ), double the number of different values of m . 004 10.0 points The n and quantum numbers of the last electron of an element are n = 4 and = 2 . The element is 1. a representative element. 2. a d -transition metal. correct 3. a nonmetal. 4. an f -transition metal.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
momin (rrm497) – Homework 2 – Sutcliffe – (53120) 2 5. a noble gas. Explanation: Where = 2, d electrons are filling. These are the transition metals. 005 10.0 points How many d electrons does I (atomic number 53) possess? 1. 20 correct 2. 10 3. 16 4. 53 5. 0 6. 8 7. 5 Explanation: I has 10 electrons in the 3 d orbital and 10 electrons in the 4 d orbital to give a total of 20 d electrons.
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 5

HW2 - momin(rrm497 Homework 2 Sutclie(53120 This print-out...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online