solution_pdf12 - tovar (jdt436) homework 12 Turner (59070)...

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Unformatted text preview: tovar (jdt436) homework 12 Turner (59070) 1 This print-out should have 12 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A parallel-plate capacitor of dimensions 1 . 92 cm 3 . 36 cm is separated by a 0 . 8 mm thickness of paper. Find the capacitance of this device. The dielectric constant for paper is 3.7. Correct answer: 26 . 4181 pF. Explanation: Let : = 3 . 7 , d = 0 . 8 mm = 0 . 0008 m , and A = 1 . 92 cm 3 . 36 cm = 0 . 00064512 m 2 . We apply the equation for the capacitance of a parallel-plate capacitor and find C = A d = (3 . 7) (8 . 85419 10 12 C 2 / N m 2 ) parenleftbigg . 00064512 m 2 . 0008 m parenrightbigg 1 10 12 pF 1 F = 26 . 4181 pF . 002 (part 2 of 2) 10.0 points What is the maximum charge that can be placed on the capacitor? The electric strength of paper is 1 . 6 10 7 V / m. Correct answer: 0 . 338151 c. Explanation: Let : E max = 1 . 6 10 7 V / m . Since the thickness of the paper is 0 . 0008 m, the maximum voltage that can be applied before breakdown is V max = E max d. Hence, the maximum charge is Q max = C V max = C E max d = (26 . 4181 pF)(12800 V) 1 10 12 F 1 pF 1 10 6 C 1 C = . 338151 c . 003 (part 1 of 4) 10.0 points Determine the total energy stored in a con- ducting sphere with charge Q . Hint: Use the capacitance formula for a spherical capacitor which consists of two spherical shells. Take the inner sphere to have a radius a and the outer shell to have an infinite radius. 1. U = Q 2 8 a 2 2. U = Q 2 8 a 3. U = Q 2 4 a 4. U = Q 8 a 5. U = Q 2 a 4 6. U = Q 2 8 a correct 7. U = Q 2 16 a 8. U = Q 2 a Explanation: The capacitance formula for a spherical ca- pacitor of inner radius a and outer radius b is C = ab k e ( b- a ) . If we let b , we find we can neglect a in the denominator compared to b , so C a k e = 4 a....
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solution_pdf12 - tovar (jdt436) homework 12 Turner (59070)...

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