solution_pdf18 - tovar (jdt436) homework 18 Turner (59070)...

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tovar (jdt436) – homework 18 – Turner – (59070) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 10.0 points An air-flled cylindrical capacitor has a capac- itance oF 6 p± and is 3 . 7 cm in length. The coulomb constant is 8 . 98755 × 10 9 N · m 2 / C 2 . IF the radius oF the outside conductor is 1 . 3 cm, what is the required radius oF the inner conductor? Correct answer: 0 . 922468 cm. Explanation: Let : k e = 8 . 98755 × 10 9 N · m 2 / C 2 , = 3 . 7 cm = 0 . 037 m , b = 1 . 3 cm , and C = 6 p± = 6 × 10 12 ± . The capacitance oF a cylindrical capacitor is given by C = 2 k e ln b a where a and b are the inner and outer radii, respectively. Solving For a , we obtain a = b e ℓ/ (2 k e C ) = (1 . 3 cm) e (0 . 037 m) / [2 k e (6 × 10 - 12 F)] = 0 . 922468 cm . 002 10.0 points IF the plate separation oF an isolated parallel plate capacitor is doubled, 1. the potential di²erence is halved. 2. the electric feld is doubled. 3. the charge on the each plate is halved. 4. None oF these correct 5. the charge density on each plate is dou- bled. Explanation: Q and A are constant, so E = Q A ǫ 0 = constant so that E = 2 Q 2 A ǫ 0 and V = Q C = 2 Q C = 2 Q C = 2 V . 003 (part 1 oF 2) 10.0 points Consider the system oF capacitors connected to a battery as shown below. E B 3 μ ± 3 μ ± 3 μ ± 3 μ ± 3 μ ± 3 μ ± ±ind the equivalent capacitance oF the cir- cuit. 1. C = 2 3 μ ± 2. C = 4 3 μ ± 3. C = 4 μ ± 4. C = 3 μ ± 5. C = 3 2 μ ± 6. C = 2 μ ± correct 7. C = 1 μ ± Explanation:
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tovar (jdt436) – homework 18 – Turner – (59070) 2 E B C
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This note was uploaded on 12/11/2009 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.

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solution_pdf18 - tovar (jdt436) homework 18 Turner (59070)...

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