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# solution_pdf18 - tovar(jdt436 homework 18 Turner(59070 This...

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tovar (jdt436) – homework 18 – Turner – (59070) 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points An air-filled cylindrical capacitor has a capac- itance of 6 pF and is 3 . 7 cm in length. The coulomb constant is 8 . 98755 × 10 9 N · m 2 / C 2 . If the radius of the outside conductor is 1 . 3 cm, what is the required radius of the inner conductor? Correct answer: 0 . 922468 cm. Explanation: Let : k e = 8 . 98755 × 10 9 N · m 2 / C 2 , = 3 . 7 cm = 0 . 037 m , b = 1 . 3 cm , and C = 6 pF = 6 × 10 12 F . The capacitance of a cylindrical capacitor is given by C = 2 k e ln b a where a and b are the inner and outer radii, respectively. Solving for a , we obtain a = b e ℓ/ (2 k e C ) = (1 . 3 cm) e (0 . 037 m) / [2 k e (6 × 10 - 12 F)] = 0 . 922468 cm . 002 10.0 points If the plate separation of an isolated parallel plate capacitor is doubled, 1. the potential difference is halved. 2. the electric field is doubled. 3. the charge on the each plate is halved. 4. None of these correct 5. the charge density on each plate is dou- bled. Explanation: Q and A are constant, so E = Q A ǫ 0 = constant so that E = 2 Q 2 A ǫ 0 and V = Q C = 2 Q C = 2 Q C = 2 V . 003 (part 1 of 2) 10.0 points Consider the system of capacitors connected to a battery as shown below. E B 3 μ F 3 μ F 3 μ F 3 μ F 3 μ F 3 μ F Find the equivalent capacitance of the cir- cuit. 1. C = 2 3 μ F 2. C = 4 3 μ F 3. C = 4 μ F 4. C = 3 μ F 5. C = 3 2 μ F 6. C = 2 μ F correct 7. C = 1 μ F Explanation:

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tovar (jdt436) – homework 18 – Turner – (59070) 2 E B C 1 C 2 C 3 C 4 C 5 C 6 c a b c d Let : C 1 = C = 3 μ F , C 2 = C = 3 μ F , C 3 = C = 3 μ F , C 4 = C = 3 μ F , C 5 = C = 3
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solution_pdf18 - tovar(jdt436 homework 18 Turner(59070 This...

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