This preview has intentionally blurred sections. Sign up to view the full version.
View Full DocumentThis is an unformatted preview. Sign up to view the full document.
View Full Documenttovar (jdt436) homework22 Turner (59070) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points Two long parallel wires carry the same amount of current and repel each other with a force per unit length of f = F l . If both currents are doubled and the wire separation is tripled, what is the force per unit length? 1. 3 f 2. 12 f 3. 18 f 4. 4 f 9 5. 3 f 4 6. 3 f 2 7. 2 f 9 8. 36 f 9. 4 f 3 correct 10. 6 f Explanation: f = I 1 I 2 2 r = I 2 2 r f = (2 I ) 2 2 3 r = 4 3 parenleftbigg I 2 2 r parenrightbigg = 4 3 f 002 (part 1 of 3) 10.0 points Two circular loops of radius a = 0 . 71 cm whose planes are perpendicular to a common axis and whose centers are separated by a distance = a 2 . The currents flow in the directions shown in the figure. C C A x I right = 30 A I left = 30 A Find the magnitude of the magnetic field at point A on the axis midway between the loops. Correct answer: 0 T. Explanation: At point A the B field is zero . Note: The current elements on the two coils that are diagonally opposite through A , gives d vector B contributions that cancel at point A . 003 (part 2 of 3) 10.0 points Find the magnitude of the magnetic field at point C on the axis a distance to the right of the right loop. Correct answer: 0 . 000961031 T. Explanation: Let : I = 30 A , a = 0 . 71 cm = 0 . 0071 m , and = 4 10 7 . In the text, the magnitude of the magnetic field along an axial point a distance z from the center of a current loop of radius a carrying a current I , is given by B = I a 2 2 ( a 2 + x 2 ) 3 / 2 . At point C the field from the right hand loop is in the positive x-direction, and the field from the left hand loop is in the negative x- direction. Adding the fields the two loops, with x = = a/ 2 for the right-hand loop, and x = 2 l = a for the left-hand loop, we obtain B = I a 2 2 1 a 2 + a 4 2 3 / 2 tovar (jdt436) homework22 Turner (59070) 2- parenleftbigg 1 a 2 + a 2 parenrightbigg 3 / 2 bracketrightBigg = I 2 a bracketleftBigg parenleftbigg 4 5 parenrightbigg 3 / 2- parenleftbigg 1 2 parenrightbigg 3 / 2 bracketrightBigg = (4 10 7 ) (30 A) 2 (0 . 0071 m) (0 . 361988)... View Full Document
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Documentsolution_pdf23
solution_pdf24
solution_pdf25
solution_pdf17
solution_pdf40
solution_pdf14
hw 22
HW 22
hw18-solutions
ohw18-solutions
hw 18
Copyright © 2015. Course Hero, Inc.
Course Hero is not sponsored or endorsed by any college or university.