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Unformatted text preview: would travel faster than the heavy chlorine molecule. 3) a) Ca=40.1g/mol (52.5g) \ (40.1 g/mol) = 1.259 mol (1.259 mol) x (6.02 x 10 23 mol) = 7.579 x 10 23 atoms of Ca There are 7.9 x 10 23 atoms of Ca in 52.5g of Ca metal b) 1.5mol x 6.02 x 10 23 = 9.03 x 10 23 There are 9.03 x 10 23 atoms of C in 1.5 mol c) 1.5mol x 6.02 x 10 23 = 9.03 x 10 23 There are 9.03 x 10 23 atoms of CO 2 in 1.5 mol 4) a) [ (P 1 V 1 ) / T 1 ] = [ (P 2 V 2 ) / T 2 ] V 1 = ? P 1 = 0.75 atm. T 1 = 243 K V 2 = 255 L P 2 = 1.25 atm. T 2 = 313 K V= [ (255L x 1.25atm.) / 313K ] x 243K / 0.75atm = 329.952 L The volume of gas would be 329.952 L at 30 o C and 0.75 atm....
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This note was uploaded on 12/13/2009 for the course ENGG ENGL 1199 taught by Professor Bruseski during the Spring '09 term at University of the BíoBío.
 Spring '09
 Bruseski

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