This preview shows pages 1–3. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: would travel faster than the heavy chlorine molecule. 3) a) Ca=40.1g/mol (52.5g) \ (40.1 g/mol) = 1.259 mol (1.259 mol) x (6.02 x 10 23 mol) = 7.579 x 10 23 atoms of Ca There are 7.9 x 10 23 atoms of Ca in 52.5g of Ca metal b) 1.5mol x 6.02 x 10 23 = 9.03 x 10 23 There are 9.03 x 10 23 atoms of C in 1.5 mol c) 1.5mol x 6.02 x 10 23 = 9.03 x 10 23 There are 9.03 x 10 23 atoms of CO 2 in 1.5 mol 4) a) [ (P 1 V 1 ) / T 1 ] = [ (P 2 V 2 ) / T 2 ] V 1 = ? P 1 = 0.75 atm. T 1 = 243 K V 2 = 255 L P 2 = 1.25 atm. T 2 = 313 K V= [ (255L x 1.25atm.) / 313K ] x 243K / 0.75atm = 329.952 L The volume of gas would be 329.952 L at 30 o C and 0.75 atm....
View Full
Document
 Spring '09
 Bruseski

Click to edit the document details